mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
synced 2025-01-10 18:48:13 +08:00
175 lines
19 KiB
JSON
175 lines
19 KiB
JSON
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"questionId": "1000140",
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"questionFrontendId": "LCP 22",
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"categoryTitle": "Algorithms",
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"boundTopicId": 419836,
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"title": "黑白方格画",
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"titleSlug": "ccw6C7",
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"content": "English description is not available for the problem. Please switch to Chinese.",
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"translatedTitle": "黑白方格画",
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"translatedContent": "小扣注意到秋日市集上有一个创作黑白方格画的摊位。摊主给每个顾客提供一个固定在墙上的白色画板，画板不能转动。画板上有 `n * n` 的网格。绘画规则为，小扣可以选择任意多行以及任意多列的格子涂成黑色（选择的整行、整列均需涂成黑色），所选行数、列数均可为 0。\n\n小扣希望最终的成品上需要有 `k` 个黑色格子，请返回小扣共有多少种涂色方案。\n\n注意：两个方案中任意一个相同位置的格子颜色不同，就视为不同的方案。\n\n**示例 1：**\n>输入：`n = 2, k = 2`\n>\n>输出：`4`\n> \n>解释：一共有四种不同的方案：\n>第一种方案：涂第一列；\n>第二种方案：涂第二列；\n>第三种方案：涂第一行；\n>第四种方案：涂第二行。\n\n**示例 2：**\n>输入：`n = 2, k = 1`\n> \n>输出：`0`\n> \n>解释：不可行，因为第一次涂色至少会涂两个黑格。\n\n**示例 3：**\n>输入：`n = 2, k = 4`\n> \n>输出：`1`\n>\n>解释：共有 2*2=4 个格子，仅有一种涂色方案。\n\n**限制：**\n- `1 <= n <= 6`\n- `0 <= k <= n * n`\n\n\n",
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"difficulty": "Easy",
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