leetcode-problemset/leetcode-cn/originData/buy-two-chocolates.json

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        "question": {
            "questionId": "2756",
            "questionFrontendId": "2706",
            "categoryTitle": "Algorithms",
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            "title": "Buy Two Chocolates",
            "titleSlug": "buy-two-chocolates",
            "content": "<p>You are given an integer array <code>prices</code> representing the prices of various chocolates in a store. You are also given a single integer <code>money</code>, which represents your initial amount of money.</p>\n\n<p>You must buy <strong>exactly</strong> two chocolates in such a way that you still have some <strong>non-negative</strong> leftover money. You would like to minimize the sum of the prices of the two chocolates you buy.</p>\n\n<p>Return <em>the amount of money you will have leftover after buying the two chocolates</em>. If there is no way for you to buy two chocolates without ending up in debt, return <code>money</code>. Note that the leftover must be non-negative.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> prices = [1,2,2], money = 3\n<strong>Output:</strong> 0\n<strong>Explanation:</strong> Purchase the chocolates priced at 1 and 2 units respectively. You will have 3 - 3 = 0 units of money afterwards. Thus, we return 0.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> prices = [3,2,3], money = 3\n<strong>Output:</strong> 3\n<strong>Explanation:</strong> You cannot buy 2 chocolates without going in debt, so we return 3.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>2 &lt;= prices.length &lt;= 50</code></li>\n\t<li><code>1 &lt;= prices[i] &lt;= 100</code></li>\n\t<li><code>1 &lt;= money &lt;= 100</code></li>\n</ul>\n",
            "translatedTitle": "购买两块巧克力",
            "translatedContent": "<p>给你一个整数数组&nbsp;<code>prices</code>&nbsp;，它表示一个商店里若干巧克力的价格。同时给你一个整数&nbsp;<code>money</code>&nbsp;，表示你一开始拥有的钱数。</p>\n\n<p>你必须购买 <strong>恰好&nbsp;</strong>两块巧克力，而且剩余的钱数必须是 <strong>非负数</strong>&nbsp;。同时你想最小化购买两块巧克力的总花费。</p>\n\n<p>请你返回在购买两块巧克力后，最多能剩下多少钱。如果购买任意两块巧克力都超过了你拥有的钱，请你返回 <code>money</code>&nbsp;。注意剩余钱数必须是非负数。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre><b>输入：</b>prices = [1,2,2], money = 3\n<b>输出：</b>0\n<b>解释：</b>分别购买价格为 1 和 2 的巧克力。你剩下 3 - 3 = 0 块钱。所以我们返回 0 。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre><b>输入：</b>prices = [3,2,3], money = 3\n<b>输出：</b>3\n<b>解释：</b>购买任意 2 块巧克力都会超过你拥有的钱数，所以我们返回 3 。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>2 &lt;= prices.length &lt;= 50</code></li>\n\t<li><code>1 &lt;= prices[i] &lt;= 100</code></li>\n\t<li><code>1 &lt;= money &lt;= 100</code></li>\n</ul>\n",
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