leetcode-problemset/leetcode-cn/originData/boolean-evaluation-lcci.json

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            "questionId": "1000031",
            "questionFrontendId": "面试题 08.14",
            "categoryTitle": "LCCI",
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            "title": "Boolean Evaluation LCCI",
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            "content": "<p>Given a boolean expression consisting of the symbols <code>0</code> (false), <code>1</code> (true), <code>&amp;</code> (AND), <code>|</code> (OR), and <code>^</code>&nbsp;(XOR), and a desired boolean result value result, implement a function to count the number of ways of parenthesizing the expression such that it evaluates to result.</p>\r\n\r\n<p><strong>Example 1:</strong></p>\r\n\r\n<pre>\r\n<strong>Input: </strong>s = &quot;1^0|0|1&quot;, result = 0\r\n\r\n<strong>Output: </strong>2\r\n<strong>Explanation:</strong>&nbsp;Two possible parenthesizing ways are:\r\n1^(0|(0|1))\r\n1^((0|0)|1)\r\n</pre>\r\n\r\n<p><strong>Example 2:</strong></p>\r\n\r\n<pre>\r\n<strong>Input: </strong>s = &quot;0&amp;0&amp;0&amp;1^1|0&quot;, result = 1\r\n\r\n<strong>Output: </strong>10</pre>\r\n\r\n<p><strong>Note: </strong></p>\r\n\r\n<ul>\r\n\t<li>There are no more than&nbsp;19 operators in <code>s</code>.</li>\r\n</ul>\r\n",
            "translatedTitle": "布尔运算",
            "translatedContent": "<p>给定一个布尔表达式和一个期望的布尔结果 result，布尔表达式由 <code>0</code> (false)、<code>1</code> (true)、<code>&amp;</code> (AND)、 <code>|</code> (OR) 和 <code>^</code> (XOR) 符号组成。实现一个函数，算出有几种可使该表达式得出 result 值的括号方法。</p>\n\n<p><strong>示例 1:</strong></p>\n\n<pre><strong>输入: </strong>s = &quot;1^0|0|1&quot;, result = 0\n\n<strong>输出: </strong>2\n<strong>解释:</strong>&nbsp;两种可能的括号方法是\n1^(0|(0|1))\n1^((0|0)|1)\n</pre>\n\n<p><strong>示例 2:</strong></p>\n\n<pre><strong>输入: </strong>s = &quot;0&amp;0&amp;0&amp;1^1|0&quot;, result = 1\n\n<strong>输出: </strong>10</pre>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li>运算符的数量不超过 19 个</li>\n</ul>\n",
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            "hints": [
                "我们能试试所有的可能性吗？这看起来像什么？",
                "我们可以把每种可能性都看作是每个可以放置括号的地方。这意味着围绕每个操作符，使表达式在运算符上被分割。基线条件是什么？",
                "基本情况是我们有一个值，1或0。",
                "如果你的代码看起来很长，有很多的if（基于每个可能的操作符、“目标”布尔结果和左/右侧），考虑不同部分之间的关系。尽量简化代码。它不需要大量复杂的if语句。例如，考虑<LEFT>OR<RIGHT>与<LEFT>AND<RIGHT>的表达式。两者可能都需要知道<LEFT>计算结果为true的数量。看看你可以重用哪些代码。",
                "着眼于你的递归上。有重复调用吗？可以将结果存起来吗？"
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