leetcode-problemset/leetcode-cn/originData/three-divisors.json

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            "questionId": "2083",
            "questionFrontendId": "1952",
            "categoryTitle": "Algorithms",
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            "title": "Three Divisors",
            "titleSlug": "three-divisors",
            "content": "<p>Given an integer <code>n</code>, return <code>true</code><em> if </em><code>n</code><em> has <strong>exactly three positive divisors</strong>. Otherwise, return </em><code>false</code>.</p>\n\n<p>An integer <code>m</code> is a <strong>divisor</strong> of <code>n</code> if there exists an integer <code>k</code> such that <code>n = k * m</code>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> n = 2\n<strong>Output:</strong> false\n<strong>Explantion:</strong> 2 has only two divisors: 1 and 2.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> n = 4\n<strong>Output:</strong> true\n<strong>Explantion:</strong> 4 has three divisors: 1, 2, and 4.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= n &lt;= 10<sup>4</sup></code></li>\n</ul>\n",
            "translatedTitle": "三除数",
            "translatedContent": "<p>给你一个整数 <code>n</code> 。如果 <code>n</code> <strong>恰好有三个正除数</strong> ，返回 <code>true</code><em> </em>；否则，返回<em> </em><code>false</code> 。</p>\n\n<p>如果存在整数 <code>k</code> ，满足 <code>n = k * m</code> ，那么整数 <code>m</code> 就是 <code>n</code> 的一个 <strong>除数</strong> 。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre><strong>输入：</strong>n = 2\n<strong>输出：</strong>false\n<strong>解释：</strong>2 只有两个除数：1 和 2 。</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre><strong>输入：</strong>n = 4\n<strong>输出：</strong>true\n<strong>解释：</strong>4 有三个除数：1、2 和 4 。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= n &lt;= 10<sup>4</sup></code></li>\n</ul>\n",
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                "You can count the number of divisors and just check that they are 3",
                "Beware of the case of n equal 1 as some solutions might fail in it"
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