mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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174 lines
23 KiB
JSON
174 lines
23 KiB
JSON
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"questionId": "228",
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"categoryTitle": "Algorithms",
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"boundTopicId": 1527,
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"title": "Summary Ranges",
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"content": "<p>You are given a <strong>sorted unique</strong> integer array <code>nums</code>.</p>\n\n<p>A <strong>range</strong> <code>[a,b]</code> is the set of all integers from <code>a</code> to <code>b</code> (inclusive).</p>\n\n<p>Return <em>the <strong>smallest sorted</strong> list of ranges that <strong>cover all the numbers in the array exactly</strong></em>. That is, each element of <code>nums</code> is covered by exactly one of the ranges, and there is no integer <code>x</code> such that <code>x</code> is in one of the ranges but not in <code>nums</code>.</p>\n\n<p>Each range <code>[a,b]</code> in the list should be output as:</p>\n\n<ul>\n\t<li><code>"a->b"</code> if <code>a != b</code></li>\n\t<li><code>"a"</code> if <code>a == b</code></li>\n</ul>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [0,1,2,4,5,7]\n<strong>Output:</strong> ["0->2","4->5","7"]\n<strong>Explanation:</strong> The ranges are:\n[0,2] --> "0->2"\n[4,5] --> "4->5"\n[7,7] --> "7"\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [0,2,3,4,6,8,9]\n<strong>Output:</strong> ["0","2->4","6","8->9"]\n<strong>Explanation:</strong> The ranges are:\n[0,0] --> "0"\n[2,4] --> "2->4"\n[6,6] --> "6"\n[8,9] --> "8->9"\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>0 <= nums.length <= 20</code></li>\n\t<li><code>-2<sup>31</sup> <= nums[i] <= 2<sup>31</sup> - 1</code></li>\n\t<li>All the values of <code>nums</code> are <strong>unique</strong>.</li>\n\t<li><code>nums</code> is sorted in ascending order.</li>\n</ul>\n",
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"translatedTitle": "汇总区间",
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"translatedContent": "<p>给定一个 <strong>无重复元素</strong> 的 <strong>有序</strong> 整数数组 <code>nums</code> 。</p>\n\n<p>区间 <code>[a,b]</code> 是从 <code>a</code> 到 <code>b</code>（包含）的所有整数的集合。</p>\n\n<p>返回 <em><strong>恰好覆盖数组中所有数字</strong> 的 <strong>最小有序</strong> 区间范围列表 </em>。也就是说，<code>nums</code> 的每个元素都恰好被某个区间范围所覆盖，并且不存在属于某个区间但不属于 <code>nums</code> 的数字 <code>x</code> 。</p>\n\n<p>列表中的每个区间范围 <code>[a,b]</code> 应该按如下格式输出：</p>\n\n<ul>\n\t<li><code>\"a->b\"</code> ，如果 <code>a != b</code></li>\n\t<li><code>\"a\"</code> ，如果 <code>a == b</code></li>\n</ul>\n\n<p> </p>\n\n<p><strong class=\"example\">示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [0,1,2,4,5,7]\n<strong>输出：</strong>[\"0->2\",\"4->5\",\"7\"]\n<strong>解释：</strong>区间范围是：\n[0,2] --> \"0->2\"\n[4,5] --> \"4->5\"\n[7,7] --> \"7\"\n</pre>\n\n<p><strong class=\"example\">示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [0,2,3,4,6,8,9]\n<strong>输出：</strong>[\"0\",\"2->4\",\"6\",\"8->9\"]\n<strong>解释：</strong>区间范围是：\n[0,0] --> \"0\"\n[2,4] --> \"2->4\"\n[6,6] --> \"6\"\n[8,9] --> \"8->9\"\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>0 <= nums.length <= 20</code></li>\n\t<li><code>-2<sup>31</sup> <= nums[i] <= 2<sup>31</sup> - 1</code></li>\n\t<li><code>nums</code> 中的所有值都 <strong>互不相同</strong></li>\n\t<li><code>nums</code> 按升序排列</li>\n</ul>\n",
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href=\\\"https:\\/\\/pkg.go.dev\\/github.com\\/emirpasic\\/gods@v1.18.1\\\" target=\\\"_blank\\\">https:\\/\\/pkg.go.dev\\/github.com\\/emirpasic\\/gods@v1.18.1<\\/a> \\u548c <a href=\\\"https:\\/\\/pkg.go.dev\\/github.com\\/emirpasic\\/gods\\/v2@v2.0.0-alpha\\\" target=\\\"_blank\\\">https:\\/\\/pkg.go.dev\\/github.com\\/emirpasic\\/gods\\/v2@v2.0.0-alpha<\\/a> \\u7b2c\\u4e09\\u65b9\\u5e93\\u3002<\\/p>\"],\"python3\":[\"Python3\",\"<p>\\u7248\\u672c\\uff1a<code>Python 3.11<\\/code><\\/p>\\r\\n\\r\\n<p>\\u4e3a\\u4e86\\u65b9\\u4fbf\\u8d77\\u89c1\\uff0c\\u5927\\u90e8\\u5206\\u5e38\\u7528\\u5e93\\u5df2\\u7ecf\\u88ab\\u81ea\\u52a8 \\u5bfc\\u5165\\uff0c\\u5982<a href=\\\"https:\\/\\/docs.python.org\\/3\\/library\\/array.html\\\" target=\\\"_blank\\\">array<\\/a>, <a href=\\\"https:\\/\\/docs.python.org\\/3\\/library\\/bisect.html\\\" target=\\\"_blank\\\">bisect<\\/a>, <a href=\\\"https:\\/\\/docs.python.org\\/3\\/library\\/collections.html\\\" target=\\\"_blank\\\">collections<\\/a>\\u3002 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target=\\\"_blank\\\">itertools<\\/a><\\/p>\"],\"php\":[\"PHP\",\"<p><code>PHP 8.2<\\/code>.<\\/p>\\r\\n\\r\\n<p>With bcmath module.<\\/p>\"],\"typescript\":[\"TypeScript\",\"<p>TypeScript 5.7.3<\\/p>\\r\\n\\r\\n<p>Compile Options: --alwaysStrict --strictBindCallApply --strictFunctionTypes --target ES2024<\\/p>\\r\\n\\r\\n<p><a href=\\\"https:\\/\\/lodash.com\\\" target=\\\"_blank\\\">lodash.js<\\/a> \\u5e93\\u5df2\\u7ecf\\u9ed8\\u8ba4\\u88ab\\u5305\\u542b\\u3002<\\/p>\\r\\n\\r\\n<p> \\u60a8\\u53ef\\u4f7f\\u7528 <a href=\\\"https:\\/\\/datastructures-js.info\\/docs\\\" target=\\\"_blank\\\"> datastructures-js <\\/a>\\u5e93\\u6240\\u63d0\\u4f9b\\u7684\\u6570\\u636e\\u7ed3\\u6784\\u3002<\\/p>\"],\"racket\":[\"Racket\",\"<p><a href=\\\"https:\\/\\/docs.racket-lang.org\\/guide\\/performance.html#%28tech._c%29\\\" target=\\\"_blank\\\">Racket CS<\\/a> v8.15<\\/p>\\r\\n\\r\\n<p>\\u4f7f\\u7528 #lang racket<\\/p>\\r\\n\\r\\n<p>\\u5df2\\u9884\\u5148 (require data\\/gvector data\\/queue 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target=\\\"_blank\\\">\\u300c\\u4ed3\\u9889\\u7f16\\u7a0b\\u8bed\\u8a00\\u5f00\\u53d1\\u6307\\u5357\\u300d<\\/a><\\/p>\"]}",
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