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"categoryTitle": "Algorithms",
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"title": "Sum of Elements With Frequency Divisible by K",
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"content": "<p>You are given an integer array <code>nums</code> and an integer <code>k</code>.</p>\n\n<p>Return an integer denoting the <strong>sum</strong> of all elements in <code>nums</code> whose <strong><span data-keyword=\"frequency-array\">frequency</span></strong> is divisible by <code>k</code>, or 0 if there are no such elements.</p>\n\n<p><strong>Note:</strong> An element is included in the sum <strong>exactly</strong> as many times as it appears in the array if its total frequency is divisible by <code>k</code>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">nums = [1,2,2,3,3,3,3,4], k = 2</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">16</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<ul>\n\t<li>The number 1 appears once (odd frequency).</li>\n\t<li>The number 2 appears twice (even frequency).</li>\n\t<li>The number 3 appears four times (even frequency).</li>\n\t<li>The number 4 appears once (odd frequency).</li>\n</ul>\n\n<p>So, the total sum is <code>2 + 2 + 3 + 3 + 3 + 3 = 16</code>.</p>\n</div>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">nums = [1,2,3,4,5], k = 2</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">0</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<p>There are no elements that appear an even number of times, so the total sum is 0.</p>\n</div>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">nums = [4,4,4,1,2,3], k = 3</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">12</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<ul>\n\t<li>The number 1 appears once.</li>\n\t<li>The number 2 appears once.</li>\n\t<li>The number 3 appears once.</li>\n\t<li>The number 4 appears three times.</li>\n</ul>\n\n<p>So, the total sum is <code>4 + 4 + 4 = 12</code>.</p>\n</div>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 100</code></li>\n\t<li><code>1 &lt;= nums[i] &lt;= 100</code></li>\n\t<li><code>1 &lt;= k &lt;= 100</code></li>\n</ul>\n",
"translatedTitle": "出现次数能被 K 整除的元素总和",
"translatedContent": "<p>给你一个整数数组 <code>nums</code> 和一个整数 <code>k</code>。</p>\n\n<p>请返回一个整数,表示 <code>nums</code> 中所有其 <strong>出现次数</strong> 能被 <code>k</code> 整除的元素的<strong>总和</strong>;如果没有这样的元素,则返回 0 。</p>\n\n<p><strong>注意:</strong> 若某个元素在数组中的总出现次数能被 <code>k</code> 整除,则它在求和中会被计算 <strong>恰好</strong> 与其出现次数相同的次数。</p>\n\n<p>元素 <code>x</code> 的&nbsp;<strong>出现次数&nbsp;</strong>指它在数组中出现的次数。</p>\n\n<p>&nbsp;</p>\n\n<p><strong class=\"example\">示例 1</strong></p>\n\n<div class=\"example-block\">\n<p><strong>输入:</strong> <span class=\"example-io\">nums = [1,2,2,3,3,3,3,4], k = 2</span></p>\n\n<p><strong>输出:</strong> <span class=\"example-io\">16</span></p>\n\n<p><strong>解释:</strong></p>\n\n<ul>\n\t<li>数字 1 出现 1 次(奇数次)。</li>\n\t<li>数字 2 出现 2 次(偶数次)。</li>\n\t<li>数字 3 出现 4 次(偶数次)。</li>\n\t<li>数字 4 出现 1 次(奇数次)。</li>\n</ul>\n\n<p>因此总和为 <code>2 + 2 + 3 + 3 + 3 + 3 = 16</code>。</p>\n</div>\n\n<p><strong class=\"example\">示例 2</strong></p>\n\n<div class=\"example-block\">\n<p><strong>输入:</strong> <span class=\"example-io\">nums = [1,2,3,4,5], k = 2</span></p>\n\n<p><strong>输出:</strong> <span class=\"example-io\">0</span></p>\n\n<p><strong>解释:</strong></p>\n\n<p>没有元素出现偶数次,因此总和为 0。</p>\n</div>\n\n<p><strong class=\"example\">示例 3</strong></p>\n\n<div class=\"example-block\">\n<p><strong>输入:</strong> <span class=\"example-io\">nums = [4,4,4,1,2,3], k = 3</span></p>\n\n<p><strong>输出:</strong> <span class=\"example-io\">12</span></p>\n\n<p><strong>解释:</strong></p>\n\n<ul>\n\t<li>数字 1 出现 1 次。</li>\n\t<li>数字 2 出现 1 次。</li>\n\t<li>数字 3 出现 1 次。</li>\n\t<li>数字 4 出现 3 次。</li>\n</ul>\n\n<p>因此总和为 <code>4 + 4 + 4 = 12</code>。</p>\n</div>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 100</code></li>\n\t<li><code>1 &lt;= nums[i] &lt;= 100</code></li>\n\t<li><code>1 &lt;= k &lt;= 100</code></li>\n</ul>\n",
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