mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
synced 2025-10-24 06:18:57 +08:00
186 lines
23 KiB
JSON
186 lines
23 KiB
JSON
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"title": "Next Greater Element II",
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"content": "<p>Given a circular integer array <code>nums</code> (i.e., the next element of <code>nums[nums.length - 1]</code> is <code>nums[0]</code>), return <em>the <strong>next greater number</strong> for every element in</em> <code>nums</code>.</p>\n\n<p>The <strong>next greater number</strong> of a number <code>x</code> is the first greater number to its traversing-order next in the array, which means you could search circularly to find its next greater number. If it doesn't exist, return <code>-1</code> for this number.</p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,2,1]\n<strong>Output:</strong> [2,-1,2]\nExplanation: The first 1's next greater number is 2; \nThe number 2 can't find next greater number. \nThe second 1's next greater number needs to search circularly, which is also 2.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,2,3,4,3]\n<strong>Output:</strong> [2,3,4,-1,4]\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 <= nums.length <= 10<sup>4</sup></code></li>\n\t<li><code>-10<sup>9</sup> <= nums[i] <= 10<sup>9</sup></code></li>\n</ul>\n",
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"translatedTitle": "下一个更大元素 II",
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"translatedContent": "<p>给定一个循环数组 <code>nums</code> （ <code>nums[nums.length - 1]</code> 的下一个元素是 <code>nums[0]</code> ），返回 <em><code>nums</code> 中每个元素的 <strong>下一个更大元素</strong></em> 。</p>\n\n<p>数字 <code>x</code> 的 <strong>下一个更大的元素</strong> 是按数组遍历顺序，这个数字之后的第一个比它更大的数，这意味着你应该循环地搜索它的下一个更大的数。如果不存在，则输出 <code>-1</code> 。</p>\n\n<p> </p>\n\n<p><strong>示例 1:</strong></p>\n\n<pre>\n<strong>输入:</strong> nums = [1,2,1]\n<strong>输出:</strong> [2,-1,2]\n<strong>解释:</strong> 第一个 1 的下一个更大的数是 2；\n数字 2 找不到下一个更大的数； \n第二个 1 的下一个最大的数需要循环搜索，结果也是 2。\n</pre>\n\n<p><strong>示例 2:</strong></p>\n\n<pre>\n<strong>输入:</strong> nums = [1,2,3,4,3]\n<strong>输出:</strong> [2,3,4,-1,4]\n</pre>\n\n<p> </p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>1 <= nums.length <= 10<sup>4</sup></code></li>\n\t<li><code>-10<sup>9</sup> <= nums[i] <= 10<sup>9</sup></code></li>\n</ul>\n",
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