leetcode-problemset/leetcode-cn/originData/maximum-product-of-two-elements-in-an-array.json

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            "title": "Maximum Product of Two Elements in an Array",
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            "content": "Given the array of integers <code>nums</code>, you will choose two different indices <code>i</code> and <code>j</code> of that array. <em>Return the maximum value of</em> <code>(nums[i]-1)*(nums[j]-1)</code>.\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [3,4,5,2]\n<strong>Output:</strong> 12 \n<strong>Explanation:</strong> If you choose the indices i=1 and j=2 (indexed from 0), you will get the maximum value, that is, (nums[1]-1)*(nums[2]-1) = (4-1)*(5-1) = 3*4 = 12. \n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,5,4,5]\n<strong>Output:</strong> 16\n<strong>Explanation:</strong> Choosing the indices i=1 and j=3 (indexed from 0), you will get the maximum value of (5-1)*(5-1) = 16.\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [3,7]\n<strong>Output:</strong> 12\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>2 &lt;= nums.length &lt;= 500</code></li>\n\t<li><code>1 &lt;= nums[i] &lt;= 10^3</code></li>\n</ul>\n",
            "translatedTitle": "数组中两元素的最大乘积",
            "translatedContent": "<p>给你一个整数数组 <code>nums</code>，请你选择数组的两个不同下标 <code>i</code> 和 <code>j</code><em>，</em>使 <code>(nums[i]-1)*(nums[j]-1)</code> 取得最大值。</p>\n\n<p>请你计算并返回该式的最大值。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre><strong>输入：</strong>nums = [3,4,5,2]\n<strong>输出：</strong>12 \n<strong>解释：</strong>如果选择下标 i=1 和 j=2（下标从 0 开始），则可以获得最大值，(nums[1]-1)*(nums[2]-1) = (4-1)*(5-1) = 3*4 = 12 。 \n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre><strong>输入：</strong>nums = [1,5,4,5]\n<strong>输出：</strong>16\n<strong>解释：</strong>选择下标 i=1 和 j=3（下标从 0 开始），则可以获得最大值 (5-1)*(5-1) = 16 。\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre><strong>输入：</strong>nums = [3,7]\n<strong>输出：</strong>12\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>2 &lt;= nums.length &lt;= 500</code></li>\n\t<li><code>1 &lt;= nums[i] &lt;= 10^3</code></li>\n</ul>\n",
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