leetcode-problemset/leetcode-cn/originData/increasing-triplet-subsequence.json

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            "title": "Increasing Triplet Subsequence",
            "titleSlug": "increasing-triplet-subsequence",
            "content": "<p>Given an integer array <code>nums</code>, return <code>true</code><em> if there exists a triple of indices </em><code>(i, j, k)</code><em> such that </em><code>i &lt; j &lt; k</code><em> and </em><code>nums[i] &lt; nums[j] &lt; nums[k]</code>. If no such indices exists, return <code>false</code>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,2,3,4,5]\n<strong>Output:</strong> true\n<strong>Explanation:</strong> Any triplet where i &lt; j &lt; k is valid.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [5,4,3,2,1]\n<strong>Output:</strong> false\n<strong>Explanation:</strong> No triplet exists.\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [2,1,5,0,4,6]\n<strong>Output:</strong> true\n<strong>Explanation:</strong> One of the valid triplet is (3, 4, 5), because nums[3] == 0 &lt; nums[4] == 4 &lt; nums[5] == 6.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 5 * 10<sup>5</sup></code></li>\n\t<li><code>-2<sup>31</sup> &lt;= nums[i] &lt;= 2<sup>31</sup> - 1</code></li>\n</ul>\n\n<p>&nbsp;</p>\n<strong>Follow up:</strong> Could you implement a solution that runs in <code>O(n)</code> time complexity and <code>O(1)</code> space complexity?",
            "translatedTitle": "递增的三元子序列",
            "translatedContent": "<p>给你一个整数数组&nbsp;<code>nums</code> ，判断这个数组中是否存在长度为 <code>3</code> 的递增子序列。</p>\n\n<p>如果存在这样的三元组下标 <code>(i, j, k)</code>&nbsp;且满足 <code>i &lt; j &lt; k</code> ，使得&nbsp;<code>nums[i] &lt; nums[j] &lt; nums[k]</code> ，返回 <code>true</code> ；否则，返回 <code>false</code> 。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [1,2,3,4,5]\n<strong>输出：</strong>true\n<strong>解释：</strong>任何 i &lt; j &lt; k 的三元组都满足题意\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [5,4,3,2,1]\n<strong>输出：</strong>false\n<strong>解释：</strong>不存在满足题意的三元组</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [2,1,5,0,4,6]\n<strong>输出：</strong>true\n<strong>解释：</strong>其中一个满足题意的三元组是 (3, 4, 5)，因为 nums[3] == 0 &lt; nums[4] == 4 &lt; nums[5] == 6\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 5 * 10<sup>5</sup></code></li>\n\t<li><code>-2<sup>31</sup> &lt;= nums[i] &lt;= 2<sup>31</sup> - 1</code></li>\n</ul>\n\n<p>&nbsp;</p>\n\n<p><strong>进阶：</strong>你能实现时间复杂度为 <code>O(n)</code> ，空间复杂度为 <code>O(1)</code> 的解决方案吗？</p>\n",
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