leetcode-problemset/leetcode-cn/originData/count-primes.json

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            "title": "Count Primes",
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            "content": "<p>Given an integer <code>n</code>, return <em>the number of prime numbers that are strictly less than</em> <code>n</code>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> n = 10\n<strong>Output:</strong> 4\n<strong>Explanation:</strong> There are 4 prime numbers less than 10, they are 2, 3, 5, 7.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> n = 0\n<strong>Output:</strong> 0\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> n = 1\n<strong>Output:</strong> 0\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>0 &lt;= n &lt;= 5 * 10<sup>6</sup></code></li>\n</ul>\n",
            "translatedTitle": "计数质数",
            "translatedContent": "<p>给定整数 <code>n</code> ，返回 <em>所有小于非负整数&nbsp;<code>n</code>&nbsp;的质数的数量</em> 。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>n = 10\n<strong>输出：</strong>4\n<strong>解释：</strong>小于 10 的质数一共有 4 个, 它们是 2, 3, 5, 7 。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>n = 0\n<strong>输出：</strong>0\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>n = 1\n<strong>输出</strong>：0\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>0 &lt;= n &lt;= 5 * 10<sup>6</sup></code></li>\n</ul>\n",
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            "hints": [
                "Checking all the integers in the range [1, n - 1] is not efficient. Think about a better approach.",
                "Since most of the numbers are not primes, we need a fast approach to exclude the non-prime integers.",
                "Use Sieve of Eratosthenes."
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