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{
"data": {
"question": {
"questionId": "1080",
"questionFrontendId": "1023",
"categoryTitle": "Algorithms",
"boundTopicId": 3364,
"title": "Camelcase Matching",
"titleSlug": "camelcase-matching",
"content": "<p>Given an array of strings <code>queries</code> and a string <code>pattern</code>, return a boolean array <code>answer</code> where <code>answer[i]</code> is <code>true</code> if <code>queries[i]</code> matches <code>pattern</code>, and <code>false</code> otherwise.</p>\n\n<p>A query word <code>queries[i]</code> matches <code>pattern</code> if you can insert lowercase English letters into the pattern so that it equals the query. You may insert a character at any position in pattern or you may choose not to insert any characters <strong>at all</strong>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> queries = [&quot;FooBar&quot;,&quot;FooBarTest&quot;,&quot;FootBall&quot;,&quot;FrameBuffer&quot;,&quot;ForceFeedBack&quot;], pattern = &quot;FB&quot;\n<strong>Output:</strong> [true,false,true,true,false]\n<strong>Explanation:</strong> &quot;FooBar&quot; can be generated like this &quot;F&quot; + &quot;oo&quot; + &quot;B&quot; + &quot;ar&quot;.\n&quot;FootBall&quot; can be generated like this &quot;F&quot; + &quot;oot&quot; + &quot;B&quot; + &quot;all&quot;.\n&quot;FrameBuffer&quot; can be generated like this &quot;F&quot; + &quot;rame&quot; + &quot;B&quot; + &quot;uffer&quot;.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> queries = [&quot;FooBar&quot;,&quot;FooBarTest&quot;,&quot;FootBall&quot;,&quot;FrameBuffer&quot;,&quot;ForceFeedBack&quot;], pattern = &quot;FoBa&quot;\n<strong>Output:</strong> [true,false,true,false,false]\n<strong>Explanation:</strong> &quot;FooBar&quot; can be generated like this &quot;Fo&quot; + &quot;o&quot; + &quot;Ba&quot; + &quot;r&quot;.\n&quot;FootBall&quot; can be generated like this &quot;Fo&quot; + &quot;ot&quot; + &quot;Ba&quot; + &quot;ll&quot;.\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> queries = [&quot;FooBar&quot;,&quot;FooBarTest&quot;,&quot;FootBall&quot;,&quot;FrameBuffer&quot;,&quot;ForceFeedBack&quot;], pattern = &quot;FoBaT&quot;\n<strong>Output:</strong> [false,true,false,false,false]\n<strong>Explanation:</strong> &quot;FooBarTest&quot; can be generated like this &quot;Fo&quot; + &quot;o&quot; + &quot;Ba&quot; + &quot;r&quot; + &quot;T&quot; + &quot;est&quot;.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= pattern.length, queries.length &lt;= 100</code></li>\n\t<li><code>1 &lt;= queries[i].length &lt;= 100</code></li>\n\t<li><code>queries[i]</code> and <code>pattern</code> consist of English letters.</li>\n</ul>\n",
"translatedTitle": "驼峰式匹配",
"translatedContent": "<p>给你一个字符串数组 <code>queries</code>,和一个表示模式的字符串&nbsp;<code>pattern</code>,请你返回一个布尔数组 <code>answer</code> 。只有在待查项&nbsp;<code>queries[i]</code> 与模式串&nbsp;<code>pattern</code> 匹配时,&nbsp;<code>answer[i]</code>&nbsp;才为 <code>true</code>,否则为 <code>false</code>。</p>\n\n<p>如果可以将&nbsp;<strong>小写字母&nbsp;</strong>插入模式串&nbsp;<code>pattern</code>&nbsp;得到待查询项&nbsp;<code>queries[i]</code>,那么待查询项与给定模式串匹配。您可以在模式串中的任何位置插入字符,也可以选择不插入任何字符。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1</strong></p>\n\n<pre>\n<strong>输入:</strong>queries = [\"FooBar\",\"FooBarTest\",\"FootBall\",\"FrameBuffer\",\"ForceFeedBack\"], pattern = \"FB\"\n<strong>输出:</strong>[true,false,true,true,false]\n<strong>示例:</strong>\n\"FooBar\" 可以这样生成:\"F\" + \"oo\" + \"B\" + \"ar\"。\n\"FootBall\" 可以这样生成:\"F\" + \"oot\" + \"B\" + \"all\".\n\"FrameBuffer\" 可以这样生成:\"F\" + \"rame\" + \"B\" + \"uffer\".</pre>\n\n<p><strong>示例 2</strong></p>\n\n<pre>\n<strong>输入:</strong>queries = [\"FooBar\",\"FooBarTest\",\"FootBall\",\"FrameBuffer\",\"ForceFeedBack\"], pattern = \"FoBa\"\n<strong>输出:</strong>[true,false,true,false,false]\n<strong>解释:</strong>\n\"FooBar\" 可以这样生成:\"Fo\" + \"o\" + \"Ba\" + \"r\".\n\"FootBall\" 可以这样生成:\"Fo\" + \"ot\" + \"Ba\" + \"ll\".\n</pre>\n\n<p><strong>示例 3</strong></p>\n\n<pre>\n<strong>输入:</strong>queries = [\"FooBar\",\"FooBarTest\",\"FootBall\",\"FrameBuffer\",\"ForceFeedBack\"], pattern = \"FoBaT\"\n<strong>输出:</strong>[false,true,false,false,false]\n<strong>解释: </strong>\n\"FooBarTest\" 可以这样生成:\"Fo\" + \"o\" + \"Ba\" + \"r\" + \"T\" + \"est\".\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= pattern.length, queries.length &lt;= 100</code></li>\n\t<li><code>1 &lt;= queries[i].length &lt;= 100</code></li>\n\t<li><code>queries[i]</code> 和 <code>pattern</code> 由英文字母组成</li>\n</ul>\n",
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"code": "class Solution(object):\n def camelMatch(self, queries, pattern):\n \"\"\"\n :type queries: List[str]\n :type pattern: str\n :rtype: List[bool]\n \"\"\"\n ",
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"code": "/**\n * Note: The returned array must be malloced, assume caller calls free().\n */\nbool* camelMatch(char** queries, int queriesSize, char* pattern, int* returnSize) {\n \n}",
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"hints": [
"Given a single pattern and word, how can we solve it?",
"One way to do it is using a DP (pos1, pos2) where pos1 is a pointer to the word and pos2 to the pattern and returns true if we can match the pattern with the given word.",
"We have two scenarios: The first one is when `word[pos1] == pattern[pos2]`, then the transition will be just DP(pos1 + 1, pos2 + 1). The second scenario is when `word[pos1]` is lowercase then we can add this character to the pattern so that the transition is just DP(pos1 + 1, pos2)\r\nThe case base is `if (pos1 == n && pos2 == m) return true;` Where n and m are the sizes of the strings word and pattern respectively."
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