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{
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"question": {
"questionId": "3502",
"questionFrontendId": "3325",
"categoryTitle": "Algorithms",
"boundTopicId": 2956137,
"title": "Count Substrings With K-Frequency Characters I",
"titleSlug": "count-substrings-with-k-frequency-characters-i",
"content": "<p>Given a string <code>s</code> and an integer <code>k</code>, return the total number of <span data-keyword=\"substring-nonempty\">substrings</span> of <code>s</code> where <strong>at least one</strong> character appears <strong>at least</strong> <code>k</code> times.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">s = &quot;abacb&quot;, k = 2</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">4</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<p>The valid substrings are:</p>\n\n<ul>\n\t<li><code>&quot;aba&quot;</code> (character <code>&#39;a&#39;</code> appears 2 times).</li>\n\t<li><code>&quot;abac&quot;</code> (character <code>&#39;a&#39;</code> appears 2 times).</li>\n\t<li><code>&quot;abacb&quot;</code> (character <code>&#39;a&#39;</code> appears 2 times).</li>\n\t<li><code>&quot;bacb&quot;</code> (character <code>&#39;b&#39;</code> appears 2 times).</li>\n</ul>\n</div>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">s = &quot;abcde&quot;, k = 1</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">15</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<p>All substrings are valid because every character appears at least once.</p>\n</div>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= s.length &lt;= 3000</code></li>\n\t<li><code>1 &lt;= k &lt;= s.length</code></li>\n\t<li><code>s</code> consists only of lowercase English letters.</li>\n</ul>\n",
"translatedTitle": "字符至少出现 K 次的子字符串 I",
"translatedContent": "<p>给你一个字符串 <code>s</code> 和一个整数 <code>k</code>,在 <code>s</code> 的所有子字符串中,请你统计并返回 <strong>至少有一个 </strong>字符 <strong>至少出现</strong> <code>k</code> 次的子字符串总数。</p>\n\n<p><strong>子字符串 </strong>是字符串中的一个连续、<b> 非空</b> 的字符序列。</p>\n\n<p>&nbsp;</p>\n\n<p><strong class=\"example\">示例 1</strong></p>\n\n<div class=\"example-block\">\n<p><strong>输入:</strong> <span class=\"example-io\">s = \"abacb\", k = 2</span></p>\n\n<p><strong>输出:</strong> <span class=\"example-io\">4</span></p>\n\n<p><strong>解释:</strong></p>\n\n<p>符合条件的子字符串如下:</p>\n\n<ul>\n\t<li><code>\"aba\"</code>(字符 <code>'a'</code> 出现 2 次)。</li>\n\t<li><code>\"abac\"</code>(字符 <code>'a'</code> 出现 2 次)。</li>\n\t<li><code>\"abacb\"</code>(字符 <code>'a'</code> 出现 2 次)。</li>\n\t<li><code>\"bacb\"</code>(字符 <code>'b'</code> 出现 2 次)。</li>\n</ul>\n</div>\n\n<p><strong class=\"example\">示例 2</strong></p>\n\n<div class=\"example-block\">\n<p><strong>输入:</strong> <span class=\"example-io\">s = \"abcde\", k = 1</span></p>\n\n<p><strong>输出:</strong> <span class=\"example-io\">15</span></p>\n\n<p><strong>解释:</strong></p>\n\n<p>所有子字符串都有效,因为每个字符至少出现一次。</p>\n</div>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= s.length &lt;= 3000</code></li>\n\t<li><code>1 &lt;= k &lt;= s.length</code></li>\n\t<li><code>s</code> 仅由小写英文字母组成。</li>\n</ul>\n",
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"Fix the <code>left</code> index of the substring.",
"For the fixed <code>left</code> index, find the first <code>right</code> index for which substring <code>s[left..right]</code> satisfies the condition.",
"Every substring that starts at <code>left</code> and ends after <code>right</code> satisfies the condition."
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