leetcode-problemset/leetcode-cn/originData/construct-the-minimum-bitwise-array-i.json

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        "question": {
            "questionId": "3605",
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            "title": "Construct the Minimum Bitwise Array I",
            "titleSlug": "construct-the-minimum-bitwise-array-i",
            "content": "<p>You are given an array <code>nums</code> consisting of <code>n</code> <span data-keyword=\"prime-number\">prime</span> integers.</p>\n\n<p>You need to construct an array <code>ans</code> of length <code>n</code>, such that, for each index <code>i</code>, the bitwise <code>OR</code> of <code>ans[i]</code> and <code>ans[i] + 1</code> is equal to <code>nums[i]</code>, i.e. <code>ans[i] OR (ans[i] + 1) == nums[i]</code>.</p>\n\n<p>Additionally, you must <strong>minimize</strong> each value of <code>ans[i]</code> in the resulting array.</p>\n\n<p>If it is <em>not possible</em> to find such a value for <code>ans[i]</code> that satisfies the <strong>condition</strong>, then set <code>ans[i] = -1</code>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">nums = [2,3,5,7]</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">[-1,1,4,3]</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<ul>\n\t<li>For <code>i = 0</code>, as there is no value for <code>ans[0]</code> that satisfies <code>ans[0] OR (ans[0] + 1) = 2</code>, so <code>ans[0] = -1</code>.</li>\n\t<li>For <code>i = 1</code>, the smallest <code>ans[1]</code> that satisfies <code>ans[1] OR (ans[1] + 1) = 3</code> is <code>1</code>, because <code>1 OR (1 + 1) = 3</code>.</li>\n\t<li>For <code>i = 2</code>, the smallest <code>ans[2]</code> that satisfies <code>ans[2] OR (ans[2] + 1) = 5</code> is <code>4</code>, because <code>4 OR (4 + 1) = 5</code>.</li>\n\t<li>For <code>i = 3</code>, the smallest <code>ans[3]</code> that satisfies <code>ans[3] OR (ans[3] + 1) = 7</code> is <code>3</code>, because <code>3 OR (3 + 1) = 7</code>.</li>\n</ul>\n</div>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">nums = [11,13,31]</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">[9,12,15]</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<ul>\n\t<li>For <code>i = 0</code>, the smallest <code>ans[0]</code> that satisfies <code>ans[0] OR (ans[0] + 1) = 11</code> is <code>9</code>, because <code>9 OR (9 + 1) = 11</code>.</li>\n\t<li>For <code>i = 1</code>, the smallest <code>ans[1]</code> that satisfies <code>ans[1] OR (ans[1] + 1) = 13</code> is <code>12</code>, because <code>12 OR (12 + 1) = 13</code>.</li>\n\t<li>For <code>i = 2</code>, the smallest <code>ans[2]</code> that satisfies <code>ans[2] OR (ans[2] + 1) = 31</code> is <code>15</code>, because <code>15 OR (15 + 1) = 31</code>.</li>\n</ul>\n</div>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 100</code></li>\n\t<li><code>2 &lt;= nums[i] &lt;= 1000</code></li>\n\t<li><code>nums[i]</code> is a prime number.</li>\n</ul>\n",
            "translatedTitle": "构造最小位运算数组 I",
            "translatedContent": "<p>给你一个长度为 <code>n</code>&nbsp;的<span data-keyword=\"prime\">质数</span>数组&nbsp;<code>nums</code>&nbsp;。你的任务是返回一个长度为 <code>n</code>&nbsp;的数组 <code>ans</code>&nbsp;，对于每个下标 <code>i</code>&nbsp;，以下<strong>&nbsp;条件</strong>&nbsp;均成立：</p>\n\n<ul>\n\t<li><code>ans[i] OR (ans[i] + 1) == nums[i]</code></li>\n</ul>\n\n<p>除此以外，你需要 <strong>最小化</strong>&nbsp;结果数组里每一个&nbsp;<code>ans[i]</code>&nbsp;。</p>\n\n<p>如果没法找到符合 <strong>条件</strong>&nbsp;的&nbsp;<code>ans[i]</code>&nbsp;，那么&nbsp;<code>ans[i] = -1</code>&nbsp;。</p>\n\n<p><strong>质数</strong>&nbsp;指的是一个大于 1 的自然数，且它只有 1 和自己两个因数。</p>\n\n<p>&nbsp;</p>\n\n<p><strong class=\"example\">示例 1：</strong></p>\n\n<div class=\"example-block\">\n<p><span class=\"example-io\"><b>输入：</b>nums = [2,3,5,7]</span></p>\n\n<p><span class=\"example-io\"><b>输出：</b>[-1,1,4,3]</span></p>\n\n<p><b>解释：</b></p>\n\n<ul>\n\t<li>对于&nbsp;<code>i = 0</code>&nbsp;，不存在&nbsp;<code>ans[0]</code>&nbsp;满足&nbsp;<code>ans[0] OR (ans[0] + 1) = 2</code>&nbsp;，所以&nbsp;<code>ans[0] = -1</code>&nbsp;。</li>\n\t<li>对于&nbsp;<code>i = 1</code>&nbsp;，满足 <code>ans[1] OR (ans[1] + 1) = 3</code>&nbsp;的最小&nbsp;<code>ans[1]</code>&nbsp;为&nbsp;<code>1</code>&nbsp;，因为&nbsp;<code>1 OR (1 + 1) = 3</code>&nbsp;。</li>\n\t<li>对于&nbsp;<code>i = 2</code>&nbsp;，满足 <code>ans[2] OR (ans[2] + 1) = 5</code>&nbsp;的最小 <code>ans[2]</code>&nbsp;为&nbsp;<code>4</code>&nbsp;，因为&nbsp;<code>4 OR (4 + 1) = 5</code>&nbsp;。</li>\n\t<li>对于&nbsp;<code>i = 3</code>&nbsp;，满足&nbsp;<code>ans[3] OR (ans[3] + 1) = 7</code>&nbsp;的最小&nbsp;<code>ans[3]</code>&nbsp;为&nbsp;<code>3</code>&nbsp;，因为&nbsp;<code>3 OR (3 + 1) = 7</code>&nbsp;。</li>\n</ul>\n</div>\n\n<p><strong class=\"example\">示例 2：</strong></p>\n\n<div class=\"example-block\">\n<p><span class=\"example-io\"><b>输入：</b>nums = [11,13,31]</span></p>\n\n<p><span class=\"example-io\"><b>输出：</b>[9,12,15]</span></p>\n\n<p><b>解释：</b></p>\n\n<ul>\n\t<li>对于&nbsp;<code>i = 0</code>&nbsp;，满足&nbsp;<code>ans[0] OR (ans[0] + 1) = 11</code> 的最小&nbsp;<code>ans[0]</code>&nbsp;为&nbsp;<code>9</code>&nbsp;，因为&nbsp;<code>9 OR (9 + 1) = 11</code>&nbsp;。</li>\n\t<li>对于&nbsp;<code>i = 1</code>&nbsp;，满足&nbsp;<code>ans[1] OR (ans[1] + 1) = 13</code>&nbsp;的最小&nbsp;<code>ans[1]</code>&nbsp;为&nbsp;<code>12</code>&nbsp;，因为&nbsp;<code>12 OR (12 + 1) = 13</code>&nbsp;。</li>\n\t<li>对于&nbsp;<code>i = 2</code>&nbsp;，满足&nbsp;<code>ans[2] OR (ans[2] + 1) = 31</code>&nbsp;的最小&nbsp;<code>ans[2]</code>&nbsp;为&nbsp;<code>15</code>&nbsp;，因为&nbsp;<code>15 OR (15 + 1) = 31</code>&nbsp;。</li>\n</ul>\n</div>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 100</code></li>\n\t<li><code>2 &lt;= nums[i] &lt;= 1000</code></li>\n\t<li><code>nums[i]</code>&nbsp;是一个质数。</li>\n</ul>\n",
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target=\\\"_blank\\\">\\u300c\\u4ed3\\u9889\\u7f16\\u7a0b\\u8bed\\u8a00\\u5f00\\u53d1\\u6307\\u5357\\u300d<\\/a><\\/p>\"]}",
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