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49 lines
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49 lines
2.0 KiB
HTML
<p>A <strong>swap</strong> is defined as taking two <strong>distinct</strong> positions in an array and swapping the values in them.</p>
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<p>A <strong>circular</strong> array is defined as an array where we consider the <strong>first</strong> element and the <strong>last</strong> element to be <strong>adjacent</strong>.</p>
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<p>Given a <strong>binary</strong> <strong>circular</strong> array <code>nums</code>, return <em>the minimum number of swaps required to group all </em><code>1</code><em>'s present in the array together at <strong>any location</strong></em>.</p>
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<p> </p>
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<p><strong>Example 1:</strong></p>
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<pre>
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<strong>Input:</strong> nums = [0,1,0,1,1,0,0]
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<strong>Output:</strong> 1
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<strong>Explanation:</strong> Here are a few of the ways to group all the 1's together:
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[0,<u>0</u>,<u>1</u>,1,1,0,0] using 1 swap.
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[0,1,<u>1</u>,1,<u>0</u>,0,0] using 1 swap.
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[1,1,0,0,0,0,1] using 2 swaps (using the circular property of the array).
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There is no way to group all 1's together with 0 swaps.
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Thus, the minimum number of swaps required is 1.
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</pre>
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<p><strong>Example 2:</strong></p>
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<pre>
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<strong>Input:</strong> nums = [0,1,1,1,0,0,1,1,0]
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<strong>Output:</strong> 2
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<strong>Explanation:</strong> Here are a few of the ways to group all the 1's together:
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[1,1,1,0,0,0,0,1,1] using 2 swaps (using the circular property of the array).
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[1,1,1,1,1,0,0,0,0] using 2 swaps.
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There is no way to group all 1's together with 0 or 1 swaps.
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Thus, the minimum number of swaps required is 2.
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</pre>
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<p><strong>Example 3:</strong></p>
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<pre>
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<strong>Input:</strong> nums = [1,1,0,0,1]
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<strong>Output:</strong> 0
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<strong>Explanation:</strong> All the 1's are already grouped together due to the circular property of the array.
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Thus, the minimum number of swaps required is 0.
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</pre>
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<p> </p>
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<p><strong>Constraints:</strong></p>
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<ul>
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<li><code>1 <= nums.length <= 10<sup>5</sup></code></li>
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<li><code>nums[i]</code> is either <code>0</code> or <code>1</code>.</li>
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</ul>
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