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leetcode-problemset/leetcode-cn/originData/sqrtx.json
2022-05-02 23:44:12 +08:00

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"question": {
"questionId": "69",
"questionFrontendId": "69",
"categoryTitle": "Algorithms",
"boundTopicId": 1128,
"title": "Sqrt(x)",
"titleSlug": "sqrtx",
"content": "<p>Given a non-negative integer <code>x</code>,&nbsp;compute and return <em>the square root of</em> <code>x</code>.</p>\n\n<p>Since the return type&nbsp;is an integer, the decimal digits are <strong>truncated</strong>, and only <strong>the integer part</strong> of the result&nbsp;is returned.</p>\n\n<p><strong>Note:&nbsp;</strong>You are not allowed to use any built-in exponent function or operator, such as <code>pow(x, 0.5)</code> or&nbsp;<code>x ** 0.5</code>.</p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> x = 4\n<strong>Output:</strong> 2\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> x = 8\n<strong>Output:</strong> 2\n<strong>Explanation:</strong> The square root of 8 is 2.82842..., and since the decimal part is truncated, 2 is returned.</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>0 &lt;= x &lt;= 2<sup>31</sup> - 1</code></li>\n</ul>\n",
"translatedTitle": "x 的平方根 ",
"translatedContent": "<p>给你一个非负整数 <code>x</code> ,计算并返回&nbsp;<code>x</code>&nbsp;的 <strong>算术平方根</strong> 。</p>\n\n<p>由于返回类型是整数,结果只保留 <strong>整数部分 </strong>,小数部分将被 <strong>舍去 。</strong></p>\n\n<p><strong>注意:</strong>不允许使用任何内置指数函数和算符,例如 <code>pow(x, 0.5)</code> 或者 <code>x ** 0.5</code> 。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1</strong></p>\n\n<pre>\n<strong>输入:</strong>x = 4\n<strong>输出:</strong>2\n</pre>\n\n<p><strong>示例 2</strong></p>\n\n<pre>\n<strong>输入:</strong>x = 8\n<strong>输出:</strong>2\n<strong>解释:</strong>8 的算术平方根是 2.82842..., 由于返回类型是整数,小数部分将被舍去。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>0 &lt;= x &lt;= 2<sup>31</sup> - 1</code></li>\n</ul>\n",
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"Try exploring all integers. (Credits: @annujoshi)",
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