mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
synced 2025-01-11 02:58:13 +08:00
174 lines
19 KiB
JSON
174 lines
19 KiB
JSON
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"questionId": "231",
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"categoryTitle": "Algorithms",
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"boundTopicId": 1409,
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"title": "Power of Two",
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"content": "<p>Given an integer <code>n</code>, return <em><code>true</code> if it is a power of two. Otherwise, return <code>false</code></em>.</p>\n\n<p>An integer <code>n</code> is a power of two, if there exists an integer <code>x</code> such that <code>n == 2<sup>x</sup></code>.</p>\n\n<p> </p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> n = 1\n<strong>Output:</strong> true\n<strong>Explanation: </strong>2<sup>0</sup> = 1\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> n = 16\n<strong>Output:</strong> true\n<strong>Explanation: </strong>2<sup>4</sup> = 16\n</pre>\n\n<p><strong>Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> n = 3\n<strong>Output:</strong> false\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>-2<sup>31</sup> <= n <= 2<sup>31</sup> - 1</code></li>\n</ul>\n\n<p> </p>\n<strong>Follow up:</strong> Could you solve it without loops/recursion?",
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"translatedTitle": "2 的幂",
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"translatedContent": "<p>给你一个整数 <code>n</code>，请你判断该整数是否是 2 的幂次方。如果是，返回 <code>true</code> ；否则，返回 <code>false</code> 。</p>\n\n<p>如果存在一个整数 <code>x</code> 使得 <code>n == 2<sup>x</sup></code> ，则认为 <code>n</code> 是 2 的幂次方。</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>n = 1\n<strong>输出：</strong>true\n<strong>解释：</strong>2<sup>0</sup> = 1\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>n = 16\n<strong>输出：</strong>true\n<strong>解释：</strong>2<sup>4</sup> = 16\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>n = 3\n<strong>输出：</strong>false\n</pre>\n\n<p><strong>示例 4：</strong></p>\n\n<pre>\n<strong>输入：</strong>n = 4\n<strong>输出：</strong>true\n</pre>\n\n<p><strong>示例 5：</strong></p>\n\n<pre>\n<strong>输入：</strong>n = 5\n<strong>输出：</strong>false\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>-2<sup>31</sup> <= n <= 2<sup>31</sup> - 1</code></li>\n</ul>\n\n<p> </p>\n\n<p><strong>进阶：</strong>你能够不使用循环/递归解决此问题吗？</p>\n",
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