leetcode-problemset/leetcode-cn/originData/minimum-average-difference.json

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            "title": "Minimum Average Difference",
            "titleSlug": "minimum-average-difference",
            "content": "<p>You are given a <strong>0-indexed</strong> integer array <code>nums</code> of length <code>n</code>.</p>\n\n<p>The <strong>average difference</strong> of the index <code>i</code> is the <strong>absolute</strong> <strong>difference</strong> between the average of the <strong>first</strong> <code>i + 1</code> elements of <code>nums</code> and the average of the <strong>last</strong> <code>n - i - 1</code> elements. Both averages should be <strong>rounded down</strong> to the nearest integer.</p>\n\n<p>Return<em> the index with the <strong>minimum average difference</strong></em>. If there are multiple such indices, return the <strong>smallest</strong> one.</p>\n\n<p><strong>Note:</strong></p>\n\n<ul>\n\t<li>The <strong>absolute difference</strong> of two numbers is the absolute value of their difference.</li>\n\t<li>The <strong>average</strong> of <code>n</code> elements is the <strong>sum</strong> of the <code>n</code> elements divided (<strong>integer division</strong>) by <code>n</code>.</li>\n\t<li>The average of <code>0</code> elements is considered to be <code>0</code>.</li>\n</ul>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [2,5,3,9,5,3]\n<strong>Output:</strong> 3\n<strong>Explanation:</strong>\n- The average difference of index 0 is: |2 / 1 - (5 + 3 + 9 + 5 + 3) / 5| = |2 / 1 - 25 / 5| = |2 - 5| = 3.\n- The average difference of index 1 is: |(2 + 5) / 2 - (3 + 9 + 5 + 3) / 4| = |7 / 2 - 20 / 4| = |3 - 5| = 2.\n- The average difference of index 2 is: |(2 + 5 + 3) / 3 - (9 + 5 + 3) / 3| = |10 / 3 - 17 / 3| = |3 - 5| = 2.\n- The average difference of index 3 is: |(2 + 5 + 3 + 9) / 4 - (5 + 3) / 2| = |19 / 4 - 8 / 2| = |4 - 4| = 0.\n- The average difference of index 4 is: |(2 + 5 + 3 + 9 + 5) / 5 - 3 / 1| = |24 / 5 - 3 / 1| = |4 - 3| = 1.\n- The average difference of index 5 is: |(2 + 5 + 3 + 9 + 5 + 3) / 6 - 0| = |27 / 6 - 0| = |4 - 0| = 4.\nThe average difference of index 3 is the minimum average difference so return 3.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [0]\n<strong>Output:</strong> 0\n<strong>Explanation:</strong>\nThe only index is 0 so return 0.\nThe average difference of index 0 is: |0 / 1 - 0| = |0 - 0| = 0.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>0 &lt;= nums[i] &lt;= 10<sup>5</sup></code></li>\n</ul>\n",
            "translatedTitle": "最小平均差",
            "translatedContent": "<p>给你一个下标从 <strong>0</strong>&nbsp;开始长度为 <code>n</code>&nbsp;的整数数组&nbsp;<code>nums</code>&nbsp;。</p>\n\n<p>下标 <code>i</code>&nbsp;处的 <strong>平均差</strong>&nbsp;指的是 <code>nums</code>&nbsp;中 <strong>前</strong>&nbsp;<code>i + 1</code>&nbsp;个元素平均值和 <strong>后</strong>&nbsp;<code>n - i - 1</code>&nbsp;个元素平均值的 <strong>绝对差</strong>&nbsp;。两个平均值都需要 <strong>向下取整</strong>&nbsp;到最近的整数。</p>\n\n<p>请你返回产生 <strong>最小平均差</strong>&nbsp;的下标。如果有多个下标最小平均差相等，请你返回 <strong>最小</strong>&nbsp;的一个下标。</p>\n\n<p><strong>注意：</strong></p>\n\n<ul>\n\t<li>两个数的<strong>&nbsp;绝对差</strong>&nbsp;是两者差的绝对值。</li>\n\t<li>&nbsp;<code>n</code>&nbsp;个元素的平均值是 <code>n</code>&nbsp;个元素之 <strong>和</strong>&nbsp;除以（整数除法）&nbsp;<code>n</code>&nbsp;。</li>\n\t<li><code>0</code>&nbsp;个元素的平均值视为&nbsp;<code>0</code>&nbsp;。</li>\n</ul>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre><b>输入：</b>nums = [2,5,3,9,5,3]\n<b>输出：</b>3\n<strong>解释：</strong>\n- 下标 0 处的平均差为：|2 / 1 - (5 + 3 + 9 + 5 + 3) / 5| = |2 / 1 - 25 / 5| = |2 - 5| = 3 。\n- 下标 1 处的平均差为：|(2 + 5) / 2 - (3 + 9 + 5 + 3) / 4| = |7 / 2 - 20 / 4| = |3 - 5| = 2 。\n- 下标 2 处的平均差为：|(2 + 5 + 3) / 3 - (9 + 5 + 3) / 3| = |10 / 3 - 17 / 3| = |3 - 5| = 2 。\n- 下标 3 处的平均差为：|(2 + 5 + 3 + 9) / 4 - (5 + 3) / 2| = |19 / 4 - 8 / 2| = |4 - 4| = 0 。 \n- 下标 4 处的平均差为：|(2 + 5 + 3 + 9 + 5) / 5 - 3 / 1| = |24 / 5 - 3 / 1| = |4 - 3| = 1 。\n- 下标 5 处的平均差为：|(2 + 5 + 3 + 9 + 5 + 3) / 6 - 0| = |27 / 6 - 0| = |4 - 0| = 4 。\n下标 3 处的平均差为最小平均差，所以返回 3 。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre><b>输入：</b>nums = [0]\n<b>输出：</b>0\n<strong>解释：</strong>\n唯一的下标是 0 ，所以我们返回 0 。\n下标 0 处的平均差为：|0 / 1 - 0| = |0 - 0| = 0 。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>0 &lt;= nums[i] &lt;= 10<sup>5</sup></code></li>\n</ul>\n",
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