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leetcode-problemset/leetcode-cn/originData/form-smallest-number-from-two-digit-arrays.json
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{
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"question": {
"questionId": "2668",
"questionFrontendId": "2605",
"categoryTitle": "Algorithms",
"boundTopicId": 2200357,
"title": "Form Smallest Number From Two Digit Arrays",
"titleSlug": "form-smallest-number-from-two-digit-arrays",
"content": "Given two arrays of <strong>unique</strong> digits <code>nums1</code> and <code>nums2</code>, return <em>the <strong>smallest</strong> number that contains <strong>at least</strong> one digit from each array</em>.\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums1 = [4,1,3], nums2 = [5,7]\n<strong>Output:</strong> 15\n<strong>Explanation:</strong> The number 15 contains the digit 1 from nums1 and the digit 5 from nums2. It can be proven that 15 is the smallest number we can have.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums1 = [3,5,2,6], nums2 = [3,1,7]\n<strong>Output:</strong> 3\n<strong>Explanation:</strong> The number 3 contains the digit 3 which exists in both arrays.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums1.length, nums2.length &lt;= 9</code></li>\n\t<li><code>1 &lt;= nums1[i], nums2[i] &lt;= 9</code></li>\n\t<li>All digits in each array are <strong>unique</strong>.</li>\n</ul>\n",
"translatedTitle": "从两个数字数组里生成最小数字",
"translatedContent": "给你两个只包含 1 到 9 之间数字的数组&nbsp;<code>nums1</code> 和&nbsp;<code>nums2</code>&nbsp;,每个数组中的元素 <strong>互不相同</strong>&nbsp;,请你返回 <strong>最小</strong> 的数字,两个数组都 <strong>至少</strong> 包含这个数字的某个数位。\n<p>&nbsp;</p>\n\n<p><strong>示例 1</strong></p>\n\n<pre><b>输入:</b>nums1 = [4,1,3], nums2 = [5,7]\n<b>输出:</b>15\n<b>解释:</b>数字 15 的数位 1 在 nums1 中出现,数位 5 在 nums2 中出现。15 是我们能得到的最小数字。\n</pre>\n\n<p><strong>示例 2</strong></p>\n\n<pre><b>输入:</b>nums1 = [3,5,2,6], nums2 = [3,1,7]\n<b>输出:</b>3\n<b>解释:</b>数字 3 的数位 3 在两个数组中都出现了。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums1.length, nums2.length &lt;= 9</code></li>\n\t<li><code>1 &lt;= nums1[i], nums2[i] &lt;= 9</code></li>\n\t<li>每个数组中,元素 <strong>互不相同</strong>&nbsp;。</li>\n</ul>\n",
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"How many digits will the resulting number have at most?",
"The resulting number will have either one or two digits. Try to find when each case is possible."
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