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leetcode-problemset/leetcode-cn/originData/fizz-buzz.json
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{
"data": {
"question": {
"questionId": "412",
"questionFrontendId": "412",
"categoryTitle": "Algorithms",
"boundTopicId": 1570,
"title": "Fizz Buzz",
"titleSlug": "fizz-buzz",
"content": "<p>Given an integer <code>n</code>, return <em>a string array </em><code>answer</code><em> (<strong>1-indexed</strong>) where</em>:</p>\n\n<ul>\n\t<li><code>answer[i] == &quot;FizzBuzz&quot;</code> if <code>i</code> is divisible by <code>3</code> and <code>5</code>.</li>\n\t<li><code>answer[i] == &quot;Fizz&quot;</code> if <code>i</code> is divisible by <code>3</code>.</li>\n\t<li><code>answer[i] == &quot;Buzz&quot;</code> if <code>i</code> is divisible by <code>5</code>.</li>\n\t<li><code>answer[i] == i</code> (as a string) if none of the above conditions are true.</li>\n</ul>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n<pre><strong>Input:</strong> n = 3\n<strong>Output:</strong> [\"1\",\"2\",\"Fizz\"]\n</pre><p><strong>Example 2:</strong></p>\n<pre><strong>Input:</strong> n = 5\n<strong>Output:</strong> [\"1\",\"2\",\"Fizz\",\"4\",\"Buzz\"]\n</pre><p><strong>Example 3:</strong></p>\n<pre><strong>Input:</strong> n = 15\n<strong>Output:</strong> [\"1\",\"2\",\"Fizz\",\"4\",\"Buzz\",\"Fizz\",\"7\",\"8\",\"Fizz\",\"Buzz\",\"11\",\"Fizz\",\"13\",\"14\",\"FizzBuzz\"]\n</pre>\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= n &lt;= 10<sup>4</sup></code></li>\n</ul>\n",
"translatedTitle": "Fizz Buzz",
"translatedContent": "<p>给你一个整数 <code>n</code> ,找出从 <code>1</code> 到 <code>n</code> 各个整数的 Fizz Buzz 表示,并用字符串数组 <code>answer</code><strong>下标从 1 开始</strong>)返回结果,其中:</p>\n\n<ul>\n\t<li><code>answer[i] == \"FizzBuzz\"</code> 如果 <code>i</code> 同时是 <code>3</code> 和 <code>5</code> 的倍数。</li>\n\t<li><code>answer[i] == \"Fizz\"</code> 如果 <code>i</code> 是 <code>3</code> 的倍数。</li>\n\t<li><code>answer[i] == \"Buzz\"</code> 如果 <code>i</code> 是 <code>5</code> 的倍数。</li>\n\t<li><code>answer[i] == i</code> (以字符串形式)如果上述条件全不满足。</li>\n</ul>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1</strong></p>\n\n<pre>\n<strong>输入:</strong>n = 3\n<strong>输出:</strong>[\"1\",\"2\",\"Fizz\"]\n</pre>\n\n<p><strong>示例 2</strong></p>\n\n<pre>\n<strong>输入:</strong>n = 5\n<strong>输出:</strong>[\"1\",\"2\",\"Fizz\",\"4\",\"Buzz\"]\n</pre>\n\n<p><strong>示例 3</strong></p>\n\n<pre>\n<strong>输入:</strong>n = 15\n<strong>输出:</strong>[\"1\",\"2\",\"Fizz\",\"4\",\"Buzz\",\"Fizz\",\"7\",\"8\",\"Fizz\",\"Buzz\",\"11\",\"Fizz\",\"13\",\"14\",\"FizzBuzz\"]</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= n &lt;= 10<sup>4</sup></code></li>\n</ul>\n",
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"code": "class Solution {\npublic:\n vector<string> fizzBuzz(int n) {\n\n }\n};",
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"code": "class Solution(object):\n def fizzBuzz(self, n):\n \"\"\"\n :type n: int\n :rtype: List[str]\n \"\"\"",
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"code": "class Solution:\n def fizzBuzz(self, n: int) -> List[str]:",
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"code": "\n\n/**\n * Note: The returned array must be malloced, assume caller calls free().\n */\nchar ** fizzBuzz(int n, int* returnSize){\n\n}",
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"code": "/**\n * @param {number} n\n * @return {string[]}\n */\nvar fizzBuzz = function(n) {\n\n};",
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"dailyRecordStatus": null,
"editorType": "CKEDITOR",
"ugcQuestionId": null,
"style": "LEETCODE",
"exampleTestcases": "3\n5\n15",
"__typename": "QuestionNode"
}
}
}