leetcode-problemset/leetcode-cn/originData/find-xor-beauty-of-array.json

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            "title": "Find Xor-Beauty of Array",
            "titleSlug": "find-xor-beauty-of-array",
            "content": "<p>You are given a <strong>0-indexed</strong> integer array <code>nums</code>.</p>\n\n<p>The <strong>effective value</strong> of three indices <code>i</code>, <code>j</code>, and <code>k</code> is defined as <code>((nums[i] | nums[j]) &amp; nums[k])</code>.</p>\n\n<p>The <strong>xor-beauty</strong> of the array is the XORing of <strong>the effective values of all the possible triplets</strong> of indices <code>(i, j, k)</code> where <code>0 &lt;= i, j, k &lt; n</code>.</p>\n\n<p>Return <em>the xor-beauty of</em> <code>nums</code>.</p>\n\n<p><strong>Note</strong> that:</p>\n\n<ul>\n\t<li><code>val1 | val2</code> is bitwise OR of <code>val1</code> and <code>val2</code>.</li>\n\t<li><code>val1 &amp; val2</code> is bitwise AND of <code>val1</code> and <code>val2</code>.</li>\n</ul>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,4]\n<strong>Output:</strong> 5\n<strong>Explanation:</strong> \nThe triplets and their corresponding effective values are listed below:\n- (0,0,0) with effective value ((1 | 1) &amp; 1) = 1\n- (0,0,1) with effective value ((1 | 1) &amp; 4) = 0\n- (0,1,0) with effective value ((1 | 4) &amp; 1) = 1\n- (0,1,1) with effective value ((1 | 4) &amp; 4) = 4\n- (1,0,0) with effective value ((4 | 1) &amp; 1) = 1\n- (1,0,1) with effective value ((4 | 1) &amp; 4) = 4\n- (1,1,0) with effective value ((4 | 4) &amp; 1) = 0\n- (1,1,1) with effective value ((4 | 4) &amp; 4) = 4 \nXor-beauty of array will be bitwise XOR of all beauties = 1 ^ 0 ^ 1 ^ 4 ^ 1 ^ 4 ^ 0 ^ 4 = 5.</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [15,45,20,2,34,35,5,44,32,30]\n<strong>Output:</strong> 34\n<strong>Explanation:</strong> <code>The xor-beauty of the given array is 34.</code>\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length&nbsp;&lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= nums[i] &lt;= 10<sup>9</sup></code></li>\n</ul>\n",
            "translatedTitle": "查询数组 Xor 美丽值",
            "translatedContent": "<p>给你一个下标从 <strong>0</strong>&nbsp;开始的整数数组&nbsp;<code>nums</code>&nbsp;。</p>\n\n<p>三个下标&nbsp;<code>i</code>&nbsp;，<code>j</code>&nbsp;和&nbsp;<code>k</code>&nbsp;的 <strong>有效值</strong>&nbsp;定义为&nbsp;<code>((nums[i] | nums[j]) &amp; nums[k])</code>&nbsp;。</p>\n\n<p>一个数组的 <strong>xor 美丽值</strong>&nbsp;是数组中所有满足&nbsp;<code>0 &lt;= i, j, k &lt; n</code>&nbsp;&nbsp;<strong>的三元组</strong>&nbsp;<code>(i, j, k)</code>&nbsp;的 <strong>有效值</strong>&nbsp;的异或结果。</p>\n\n<p>请你返回&nbsp;<code>nums</code>&nbsp;的 xor 美丽值。</p>\n\n<p><b>注意：</b></p>\n\n<ul>\n\t<li><code>val1 | val2</code>&nbsp;是&nbsp;<code>val1</code> 和&nbsp;<code>val2</code>&nbsp;的按位或。</li>\n\t<li><code>val1 &amp; val2</code>&nbsp;是&nbsp;<code>val1</code> 和&nbsp;<code>val2</code>&nbsp;的按位与。</li>\n</ul>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<b>输入：</b>nums = [1,4]\n<b>输出：</b>5\n<b>解释：</b>\n三元组和它们对应的有效值如下：\n- (0,0,0) 有效值为 ((1 | 1) &amp; 1) = 1\n- (0,0,1) 有效值为 ((1 | 1) &amp; 4) = 0\n- (0,1,0) 有效值为 ((1 | 4) &amp; 1) = 1\n- (0,1,1) 有效值为 ((1 | 4) &amp; 4) = 4\n- (1,0,0) 有效值为 ((4 | 1) &amp; 1) = 1\n- (1,0,1) 有效值为 ((4 | 1) &amp; 4) = 4\n- (1,1,0) 有效值为 ((4 | 4) &amp; 1) = 0\n- (1,1,1) 有效值为 ((4 | 4) &amp; 4) = 4 \n数组的 xor 美丽值为所有有效值的按位异或 1 ^ 0 ^ 1 ^ 4 ^ 1 ^ 4 ^ 0 ^ 4 = 5 。</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<b>输入：</b>nums = [15,45,20,2,34,35,5,44,32,30]\n<b>输出：</b>34\n<code><span style=\"\"><b>解释：</b>数组的 xor 美丽值为</span> 34 。</code>\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length&nbsp;&lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= nums[i] &lt;= 10<sup>9</sup></code></li>\n</ul>\n",
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