leetcode-problemset/leetcode-cn/originData/find-the-array-concatenation-value.json

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            "title": "Find the Array Concatenation Value",
            "titleSlug": "find-the-array-concatenation-value",
            "content": "<p>You are given a <strong>0-indexed</strong> integer array <code>nums</code>.</p>\n\n<p>The <strong>concatenation</strong> of two numbers is the number formed by concatenating their numerals.</p>\n\n<ul>\n\t<li>For example, the concatenation of <code>15</code>, <code>49</code> is <code>1549</code>.</li>\n</ul>\n\n<p>The <strong>concatenation value</strong> of <code>nums</code> is initially equal to <code>0</code>. Perform this operation until <code>nums</code> becomes empty:</p>\n\n<ul>\n\t<li>If there exists more than one number in <code>nums</code>, pick the first element and last element in <code>nums</code> respectively and add the value of their concatenation to the <strong>concatenation value</strong> of <code>nums</code>, then delete the first and last element from <code>nums</code>.</li>\n\t<li>If one element exists, add its value to the <strong>concatenation value</strong> of <code>nums</code>, then delete it.</li>\n</ul>\n\n<p>Return<em> the concatenation value of the <code>nums</code></em>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [7,52,2,4]\n<strong>Output:</strong> 596\n<strong>Explanation:</strong> Before performing any operation, nums is [7,52,2,4] and concatenation value is 0.\n - In the first operation:\nWe pick the first element, 7, and the last element, 4.\nTheir concatenation is 74, and we add it to the concatenation value, so it becomes equal to 74.\nThen we delete them from nums, so nums becomes equal to [52,2].\n - In the second operation:\nWe pick the first element, 52, and the last element, 2.\nTheir concatenation is 522, and we add it to the concatenation value, so it becomes equal to 596.\nThen we delete them from the nums, so nums becomes empty.\nSince the concatenation value is 596 so the answer is 596.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [5,14,13,8,12]\n<strong>Output:</strong> 673\n<strong>Explanation:</strong> Before performing any operation, nums is [5,14,13,8,12] and concatenation value is 0.\n - In the first operation:\nWe pick the first element, 5, and the last element, 12.\nTheir concatenation is 512, and we add it to the concatenation value, so it becomes equal to 512.\nThen we delete them from the nums, so nums becomes equal to [14,13,8].\n - In the second operation:\nWe pick the first element, 14, and the last element, 8.\nTheir concatenation is 148, and we add it to the concatenation value, so it becomes equal to 660.\nThen we delete them from the nums, so nums becomes equal to [13].\n - In the third operation:\nnums has only one element, so we pick 13 and add it to the concatenation value, so it becomes equal to 673.\nThen we delete it from nums, so nums become empty.\nSince the concatenation value is 673 so the answer is 673.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 1000</code></li>\n\t<li><code>1 &lt;= nums[i] &lt;= 10<sup>4</sup></code></li>\n</ul>\n\n<p>&nbsp;</p>\n<style type=\"text/css\">.spoilerbutton {display:block; border:dashed; padding: 0px 0px; margin:10px 0px; font-size:150%; font-weight: bold; color:#000000; background-color:cyan; outline:0; \n}\n.spoiler {overflow:hidden;}\n.spoiler > div {-webkit-transition: all 0s ease;-moz-transition: margin 0s ease;-o-transition: all 0s ease;transition: margin 0s ease;}\n.spoilerbutton[value=\"Show Message\"] + .spoiler > div {margin-top:-500%;}\n.spoilerbutton[value=\"Hide Message\"] + .spoiler {padding:5px;}\n</style>\n",
            "translatedTitle": "找出数组的串联值",
            "translatedContent": "<p>给你一个下标从 <strong>0</strong> 开始的整数数组&nbsp;<code>nums</code> 。</p>\n\n<p>现定义两个数字的 <strong>串联</strong>&nbsp;是由这两个数值串联起来形成的新数字。</p>\n\n<ul>\n\t<li>例如，<code>15</code><span style=\"\">&nbsp;和&nbsp;</span><code>49</code>&nbsp;的串联是&nbsp;<code>1549</code> 。</li>\n</ul>\n\n<p><code>nums</code>&nbsp;的 <strong>串联值</strong>&nbsp;最初等于 <code>0</code> 。执行下述操作直到&nbsp;<code>nums</code>&nbsp;变为空：</p>\n\n<ul>\n\t<li>如果&nbsp;<code>nums</code>&nbsp;中存在不止一个数字，分别选中 <code>nums</code> 中的第一个元素和最后一个元素，将二者串联得到的值加到&nbsp;<code>nums</code>&nbsp;的 <strong>串联值</strong> 上，然后从&nbsp;<code>nums</code>&nbsp;中删除第一个和最后一个元素。</li>\n\t<li>如果仅存在一个元素，则将该元素的值加到&nbsp;<code>nums</code> 的串联值上，然后删除这个元素。</li>\n</ul>\n\n<p>返回执行完所有操作后<em>&nbsp;</em><code>nums</code> 的串联值。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<b>输入：</b>nums = [7,52,2,4]\n<b>输出：</b>596\n<b>解释：</b>在执行任一步操作前，nums 为 [7,52,2,4] ，串联值为 0 。\n - 在第一步操作中：\n我们选中第一个元素 7 和最后一个元素 4 。\n二者的串联是 74 ，将其加到串联值上，所以串联值等于 74 。\n接着我们从 nums 中移除这两个元素，所以 nums 变为 [52,2] 。\n - 在第二步操作中： \n我们选中第一个元素 52 和最后一个元素 2 。 \n二者的串联是 522 ，将其加到串联值上，所以串联值等于 596 。\n接着我们从 nums 中移除这两个元素，所以 nums 变为空。\n由于串联值等于 596 ，所以答案就是 596 。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<b>输入：</b>nums = [5,14,13,8,12]\n<b>输出：</b>673\n<b>解释：</b>在执行任一步操作前，nums 为 [5,14,13,8,12] ，串联值为 0 。 \n- 在第一步操作中： \n我们选中第一个元素 5 和最后一个元素 12 。 \n二者的串联是 512 ，将其加到串联值上，所以串联值等于 512 。 \n接着我们从 nums 中移除这两个元素，所以 nums 变为 [14,13,8] 。\n- 在第二步操作中：\n我们选中第一个元素 14 和最后一个元素 8 。\n二者的串联是 148 ，将其加到串联值上，所以串联值等于 660 。\n接着我们从 nums 中移除这两个元素，所以 nums 变为 [13] 。 \n- 在第三步操作中：\nnums 只有一个元素，所以我们选中 13 并将其加到串联值上，所以串联值等于 673 。\n接着我们从 nums 中移除这个元素，所以 nums 变为空。 \n由于串联值等于 673 ，所以答案就是 673 。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 1000</code></li>\n\t<li><code>1 &lt;= nums[i] &lt;= 10<sup>4</sup></code></li>\n</ul>\n",
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