mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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168 lines
21 KiB
JSON
168 lines
21 KiB
JSON
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"title": "Best Time to Buy and Sell Stock III",
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"content": "<p>You are given an array <code>prices</code> where <code>prices[i]</code> is the price of a given stock on the <code>i<sup>th</sup></code> day.</p>\n\n<p>Find the maximum profit you can achieve. You may complete <strong>at most two transactions</strong>.</p>\n\n<p><strong>Note:</strong> You may not engage in multiple transactions simultaneously (i.e., you must sell the stock before you buy again).</p>\n\n<p> </p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> prices = [3,3,5,0,0,3,1,4]\n<strong>Output:</strong> 6\n<strong>Explanation:</strong> Buy on day 4 (price = 0) and sell on day 6 (price = 3), profit = 3-0 = 3.\nThen buy on day 7 (price = 1) and sell on day 8 (price = 4), profit = 4-1 = 3.</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> prices = [1,2,3,4,5]\n<strong>Output:</strong> 4\n<strong>Explanation:</strong> Buy on day 1 (price = 1) and sell on day 5 (price = 5), profit = 5-1 = 4.\nNote that you cannot buy on day 1, buy on day 2 and sell them later, as you are engaging multiple transactions at the same time. You must sell before buying again.\n</pre>\n\n<p><strong>Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> prices = [7,6,4,3,1]\n<strong>Output:</strong> 0\n<strong>Explanation:</strong> In this case, no transaction is done, i.e. max profit = 0.\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 <= prices.length <= 10<sup>5</sup></code></li>\n\t<li><code>0 <= prices[i] <= 10<sup>5</sup></code></li>\n</ul>\n",
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"translatedTitle": "买卖股票的最佳时机 III",
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"translatedContent": "<p>给定一个数组，它的第<em> </em><code>i</code> 个元素是一支给定的股票在第 <code>i</code><em> </em>天的价格。</p>\n\n<p>设计一个算法来计算你所能获取的最大利润。你最多可以完成 <strong>两笔 </strong>交易。</p>\n\n<p><strong>注意：</strong>你不能同时参与多笔交易（你必须在再次购买前出售掉之前的股票）。</p>\n\n<p> </p>\n\n<p><strong>示例 1:</strong></p>\n\n<pre>\n<strong>输入：</strong>prices = [3,3,5,0,0,3,1,4]\n<strong>输出：</strong>6\n<strong>解释：</strong>在第 4 天（股票价格 = 0）的时候买入，在第 6 天（股票价格 = 3）的时候卖出，这笔交易所能获得利润 = 3-0 = 3 。\n 随后，在第 7 天（股票价格 = 1）的时候买入，在第 8 天 （股票价格 = 4）的时候卖出，这笔交易所能获得利润 = 4-1 = 3 。</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>prices = [1,2,3,4,5]\n<strong>输出：</strong>4\n<strong>解释：</strong>在第 1 天（股票价格 = 1）的时候买入，在第 5 天 （股票价格 = 5）的时候卖出, 这笔交易所能获得利润 = 5-1 = 4 。 \n 注意你不能在第 1 天和第 2 天接连购买股票，之后再将它们卖出。 \n 因为这样属于同时参与了多笔交易，你必须在再次购买前出售掉之前的股票。\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>prices = [7,6,4,3,1] \n<strong>输出：</strong>0 \n<strong>解释：</strong>在这个情况下, 没有交易完成, 所以最大利润为 0。</pre>\n\n<p><strong>示例 4：</strong></p>\n\n<pre>\n<strong>输入：</strong>prices = [1]\n<strong>输出：</strong>0\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 <= prices.length <= 10<sup>5</sup></code></li>\n\t<li><code>0 <= prices[i] <= 10<sup>5</sup></code></li>\n</ul>\n",
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