mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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168 lines
19 KiB
JSON
168 lines
19 KiB
JSON
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"title": "Preimage Size of Factorial Zeroes Function",
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"content": "<p>Let <code>f(x)</code> be the number of zeroes at the end of <code>x!</code>. Recall that <code>x! = 1 * 2 * 3 * ... * x</code> and by convention, <code>0! = 1</code>.</p>\n\n<ul>\n\t<li>For example, <code>f(3) = 0</code> because <code>3! = 6</code> has no zeroes at the end, while <code>f(11) = 2</code> because <code>11! = 39916800</code> has two zeroes at the end.</li>\n</ul>\n\n<p>Given an integer <code>k</code>, return the number of non-negative integers <code>x</code> have the property that <code>f(x) = k</code>.</p>\n\n<p> </p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> k = 0\n<strong>Output:</strong> 5\n<strong>Explanation:</strong> 0!, 1!, 2!, 3!, and 4! end with k = 0 zeroes.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> k = 5\n<strong>Output:</strong> 0\n<strong>Explanation:</strong> There is no x such that x! ends in k = 5 zeroes.\n</pre>\n\n<p><strong>Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> k = 3\n<strong>Output:</strong> 5\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>0 <= k <= 10<sup>9</sup></code></li>\n</ul>\n",
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"translatedTitle": "阶乘函数后 K 个零",
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"translatedContent": "<p> <code>f(x)</code> 是 <code>x!</code> 末尾是 0 的数量。回想一下 <code>x! = 1 * 2 * 3 * ... * x</code>，且 <code>0! = 1</code> 。</p>\n\n<ul>\n\t<li>例如， <code>f(3) = 0</code> ，因为 <code>3! = 6</code> 的末尾没有 0 ；而 <code>f(11) = 2</code> ，因为 <code>11!= 39916800</code> 末端有 2 个 0 。</li>\n</ul>\n\n<p>给定 <code>k</code>，找出返回能满足 <code>f(x) = k</code> 的非负整数 <code>x</code> 的数量。</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong><strong> </strong></p>\n\n<pre>\n<strong>输入：</strong>k = 0<strong>\n输出：</strong>5<strong>\n解释：</strong>0!, 1!, 2!, 3!, 和 4! 均符合 k = 0 的条件。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>k = 5\n<strong>输出：</strong>0\n<strong>解释：</strong>没有匹配到这样的 x!，符合 k = 5 的条件。</pre>\n\n<p><strong>示例 3:</strong></p>\n\n<pre>\n<strong>输入:</strong> k = 3\n<strong>输出:</strong> 5\n</pre>\n\n<p> </p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>0 <= k <= 10<sup>9</sup></code></li>\n</ul>\n",
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