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31 lines
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31 lines
1.4 KiB
HTML
<p>Given an <code>m x n</code> binary matrix <code>mat</code>, return <em>the number of special positions in </em><code>mat</code><em>.</em></p>
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<p>A position <code>(i, j)</code> is called <strong>special</strong> if <code>mat[i][j] == 1</code> and all other elements in row <code>i</code> and column <code>j</code> are <code>0</code> (rows and columns are <strong>0-indexed</strong>).</p>
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<p> </p>
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<p><strong>Example 1:</strong></p>
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<img alt="" src="https://assets.leetcode.com/uploads/2021/12/23/special1.jpg" style="width: 244px; height: 245px;" />
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<pre>
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<strong>Input:</strong> mat = [[1,0,0],[0,0,1],[1,0,0]]
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<strong>Output:</strong> 1
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<strong>Explanation:</strong> (1, 2) is a special position because mat[1][2] == 1 and all other elements in row 1 and column 2 are 0.
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</pre>
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<p><strong>Example 2:</strong></p>
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<img alt="" src="https://assets.leetcode.com/uploads/2021/12/24/special-grid.jpg" style="width: 244px; height: 245px;" />
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<pre>
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<strong>Input:</strong> mat = [[1,0,0],[0,1,0],[0,0,1]]
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<strong>Output:</strong> 3
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<strong>Explanation:</strong> (0, 0), (1, 1) and (2, 2) are special positions.
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</pre>
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<p> </p>
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<p><strong>Constraints:</strong></p>
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<ul>
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<li><code>m == mat.length</code></li>
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<li><code>n == mat[i].length</code></li>
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<li><code>1 <= m, n <= 100</code></li>
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<li><code>mat[i][j]</code> is either <code>0</code> or <code>1</code>.</li>
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</ul>
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