mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
synced 2025-01-10 18:48:13 +08:00
45 lines
2.1 KiB
HTML
45 lines
2.1 KiB
HTML
<p>You are given a <strong>0-indexed</strong> array of <code>n</code> integers <code>arr</code>.</p>
|
|
|
|
<p>The <strong>interval</strong> between two elements in <code>arr</code> is defined as the <strong>absolute difference</strong> between their indices. More formally, the <strong>interval</strong> between <code>arr[i]</code> and <code>arr[j]</code> is <code>|i - j|</code>.</p>
|
|
|
|
<p>Return <em>an array</em> <code>intervals</code> <em>of length</em> <code>n</code> <em>where</em> <code>intervals[i]</code> <em>is <strong>the sum of intervals</strong> between </em><code>arr[i]</code><em> and each element in </em><code>arr</code><em> with the same value as </em><code>arr[i]</code><em>.</em></p>
|
|
|
|
<p><strong>Note:</strong> <code>|x|</code> is the absolute value of <code>x</code>.</p>
|
|
|
|
<p> </p>
|
|
<p><strong>Example 1:</strong></p>
|
|
|
|
<pre>
|
|
<strong>Input:</strong> arr = [2,1,3,1,2,3,3]
|
|
<strong>Output:</strong> [4,2,7,2,4,4,5]
|
|
<strong>Explanation:</strong>
|
|
- Index 0: Another 2 is found at index 4. |0 - 4| = 4
|
|
- Index 1: Another 1 is found at index 3. |1 - 3| = 2
|
|
- Index 2: Two more 3s are found at indices 5 and 6. |2 - 5| + |2 - 6| = 7
|
|
- Index 3: Another 1 is found at index 1. |3 - 1| = 2
|
|
- Index 4: Another 2 is found at index 0. |4 - 0| = 4
|
|
- Index 5: Two more 3s are found at indices 2 and 6. |5 - 2| + |5 - 6| = 4
|
|
- Index 6: Two more 3s are found at indices 2 and 5. |6 - 2| + |6 - 5| = 5
|
|
</pre>
|
|
|
|
<p><strong>Example 2:</strong></p>
|
|
|
|
<pre>
|
|
<strong>Input:</strong> arr = [10,5,10,10]
|
|
<strong>Output:</strong> [5,0,3,4]
|
|
<strong>Explanation:</strong>
|
|
- Index 0: Two more 10s are found at indices 2 and 3. |0 - 2| + |0 - 3| = 5
|
|
- Index 1: There is only one 5 in the array, so its sum of intervals to identical elements is 0.
|
|
- Index 2: Two more 10s are found at indices 0 and 3. |2 - 0| + |2 - 3| = 3
|
|
- Index 3: Two more 10s are found at indices 0 and 2. |3 - 0| + |3 - 2| = 4
|
|
</pre>
|
|
|
|
<p> </p>
|
|
<p><strong>Constraints:</strong></p>
|
|
|
|
<ul>
|
|
<li><code>n == arr.length</code></li>
|
|
<li><code>1 <= n <= 10<sup>5</sup></code></li>
|
|
<li><code>1 <= arr[i] <= 10<sup>5</sup></code></li>
|
|
</ul>
|