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leetcode-problemset/leetcode-cn/problem (English)/根据前序和后序遍历构造二叉树(English) [construct-binary-tree-from-preorder-and-postorder-traversal].html

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<p>Given two integer arrays, <code>preorder</code> and <code>postorder</code> where <code>preorder</code> is the preorder traversal of a binary tree of <strong>distinct</strong> values and <code>postorder</code> is the postorder traversal of the same tree, reconstruct and return <em>the binary tree</em>.</p>
<p>If there exist multiple answers, you can <strong>return any</strong> of them.</p>
<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>
<img alt="" src="https://assets.leetcode.com/uploads/2021/07/24/lc-prepost.jpg" style="width: 304px; height: 265px;" />
<pre>
<strong>Input:</strong> preorder = [1,2,4,5,3,6,7], postorder = [4,5,2,6,7,3,1]
<strong>Output:</strong> [1,2,3,4,5,6,7]
</pre>
<p><strong class="example">Example 2:</strong></p>
<pre>
<strong>Input:</strong> preorder = [1], postorder = [1]
<strong>Output:</strong> [1]
</pre>
<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>
<ul>
<li><code>1 &lt;= preorder.length &lt;= 30</code></li>
<li><code>1 &lt;= preorder[i] &lt;= preorder.length</code></li>
<li>All the values of <code>preorder</code> are <strong>unique</strong>.</li>
<li><code>postorder.length == preorder.length</code></li>
<li><code>1 &lt;= postorder[i] &lt;= postorder.length</code></li>
<li>All the values of <code>postorder</code> are <strong>unique</strong>.</li>
<li>It is guaranteed that <code>preorder</code> and <code>postorder</code> are the preorder traversal and postorder traversal of the same binary tree.</li>
</ul>