leetcode-problemset/leetcode-cn/originData/take-k-of-each-character-from-left-and-right.json

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        "question": {
            "questionId": "2599",
            "questionFrontendId": "2516",
            "categoryTitle": "Algorithms",
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            "title": "Take K of Each Character From Left and Right",
            "titleSlug": "take-k-of-each-character-from-left-and-right",
            "content": "<p>You are given a string <code>s</code> consisting of the characters <code>&#39;a&#39;</code>, <code>&#39;b&#39;</code>, and <code>&#39;c&#39;</code> and a non-negative integer <code>k</code>. Each minute, you may take either the <strong>leftmost</strong> character of <code>s</code>, or the <strong>rightmost</strong> character of <code>s</code>.</p>\n\n<p>Return<em> the <strong>minimum</strong> number of minutes needed for you to take <strong>at least</strong> </em><code>k</code><em> of each character, or return </em><code>-1</code><em> if it is not possible to take </em><code>k</code><em> of each character.</em></p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;aabaaaacaabc&quot;, k = 2\n<strong>Output:</strong> 8\n<strong>Explanation:</strong> \nTake three characters from the left of s. You now have two &#39;a&#39; characters, and one &#39;b&#39; character.\nTake five characters from the right of s. You now have four &#39;a&#39; characters, two &#39;b&#39; characters, and two &#39;c&#39; characters.\nA total of 3 + 5 = 8 minutes is needed.\nIt can be proven that 8 is the minimum number of minutes needed.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;a&quot;, k = 1\n<strong>Output:</strong> -1\n<strong>Explanation:</strong> It is not possible to take one &#39;b&#39; or &#39;c&#39; so return -1.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= s.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>s</code> consists of only the letters <code>&#39;a&#39;</code>, <code>&#39;b&#39;</code>, and <code>&#39;c&#39;</code>.</li>\n\t<li><code>0 &lt;= k &lt;= s.length</code></li>\n</ul>\n",
            "translatedTitle": "每种字符至少取 K 个",
            "translatedContent": "<p>给你一个由字符 <code>'a'</code>、<code>'b'</code>、<code>'c'</code> 组成的字符串 <code>s</code> 和一个非负整数 <code>k</code> 。每分钟，你可以选择取走 <code>s</code> <strong>最左侧</strong> 还是 <strong>最右侧</strong> 的那个字符。</p>\n\n<p>你必须取走每种字符 <strong>至少</strong> <code>k</code> 个，返回需要的 <strong>最少</strong> 分钟数；如果无法取到，则返回<em> </em><code>-1</code> 。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>s = \"aabaaaacaabc\", k = 2\n<strong>输出：</strong>8\n<strong>解释：</strong>\n从 s 的左侧取三个字符，现在共取到两个字符 'a' 、一个字符 'b' 。\n从 s 的右侧取五个字符，现在共取到四个字符 'a' 、两个字符 'b' 和两个字符 'c' 。\n共需要 3 + 5 = 8 分钟。\n可以证明需要的最少分钟数是 8 。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>s = \"a\", k = 1\n<strong>输出：</strong>-1\n<strong>解释：</strong>无法取到一个字符 'b' 或者 'c'，所以返回 -1 。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= s.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>s</code> 仅由字母 <code>'a'</code>、<code>'b'</code>、<code>'c'</code> 组成</li>\n\t<li><code>0 &lt;= k &lt;= s.length</code></li>\n</ul>\n",
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            "hints": [
                "Start by counting the frequency of each character and checking if it is possible.",
                "If you take x characters from the left side, what is the minimum number of characters you need to take from the right side? Find this for all values of x in the range 0 ≤ x ≤ s.length.",
                "Use a two-pointers approach to avoid computing the same information multiple times."
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