leetcode-problemset/leetcode-cn/originData/sum-of-all-odd-length-subarrays.json

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            "categoryTitle": "Algorithms",
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            "title": "Sum of All Odd Length Subarrays",
            "titleSlug": "sum-of-all-odd-length-subarrays",
            "content": "<p>Given an array of positive integers <code>arr</code>, return <em>the sum of all possible <strong>odd-length subarrays</strong> of </em><code>arr</code>.</p>\n\n<p>A <strong>subarray</strong> is a contiguous subsequence of the array.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> arr = [1,4,2,5,3]\n<strong>Output:</strong> 58\n<strong>Explanation: </strong>The odd-length subarrays of arr and their sums are:\n[1] = 1\n[4] = 4\n[2] = 2\n[5] = 5\n[3] = 3\n[1,4,2] = 7\n[4,2,5] = 11\n[2,5,3] = 10\n[1,4,2,5,3] = 15\nIf we add all these together we get 1 + 4 + 2 + 5 + 3 + 7 + 11 + 10 + 15 = 58</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> arr = [1,2]\n<strong>Output:</strong> 3\n<b>Explanation: </b>There are only 2 subarrays of odd length, [1] and [2]. Their sum is 3.</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> arr = [10,11,12]\n<strong>Output:</strong> 66\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= arr.length &lt;= 100</code></li>\n\t<li><code>1 &lt;= arr[i] &lt;= 1000</code></li>\n</ul>\n\n<p>&nbsp;</p>\n<p><strong>Follow up:</strong></p>\n\n<p>Could you solve this problem in O(n) time complexity?</p>\n",
            "translatedTitle": "所有奇数长度子数组的和",
            "translatedContent": "<p>给你一个正整数数组&nbsp;<code>arr</code>&nbsp;，请你计算所有可能的奇数长度子数组的和。</p>\n\n<p><strong>子数组</strong> 定义为原数组中的一个连续子序列。</p>\n\n<p>请你返回 <code>arr</code>&nbsp;中 <strong>所有奇数长度子数组的和</strong> 。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>arr = [1,4,2,5,3]\n<strong>输出：</strong>58\n<strong>解释：</strong>所有奇数长度子数组和它们的和为：\n[1] = 1\n[4] = 4\n[2] = 2\n[5] = 5\n[3] = 3\n[1,4,2] = 7\n[4,2,5] = 11\n[2,5,3] = 10\n[1,4,2,5,3] = 15\n我们将所有值求和得到 1 + 4 + 2 + 5 + 3 + 7 + 11 + 10 + 15 = 58</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>arr = [1,2]\n<strong>输出：</strong>3\n<strong>解释：</strong>总共只有 2 个长度为奇数的子数组，[1] 和 [2]。它们的和为 3 。</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>arr = [10,11,12]\n<strong>输出：</strong>66\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= arr.length &lt;= 100</code></li>\n\t<li><code>1 &lt;= arr[i] &lt;= 1000</code></li>\n</ul>\n\n<p>&nbsp;</p>\n\n<p><strong>进阶：</strong></p>\n\n<p>你可以设计一个 O(n) 时间复杂度的算法解决此问题吗？</p>\n",
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