leetcode-problemset/leetcode-cn/originData/smallest-value-after-replacing-with-sum-of-prime-factors.json

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            "title": "Smallest Value After Replacing With Sum of Prime Factors",
            "titleSlug": "smallest-value-after-replacing-with-sum-of-prime-factors",
            "content": "<p>You are given a positive integer <code>n</code>.</p>\n\n<p>Continuously replace <code>n</code> with the sum of its <strong>prime factors</strong>.</p>\n\n<ul>\n\t<li>Note that if a prime factor divides <code>n</code> multiple times, it should be included in the sum as many times as it divides <code>n</code>.</li>\n</ul>\n\n<p>Return <em>the smallest value </em><code>n</code><em> will take on.</em></p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> n = 15\n<strong>Output:</strong> 5\n<strong>Explanation:</strong> Initially, n = 15.\n15 = 3 * 5, so replace n with 3 + 5 = 8.\n8 = 2 * 2 * 2, so replace n with 2 + 2 + 2 = 6.\n6 = 2 * 3, so replace n with 2 + 3 = 5.\n5 is the smallest value n will take on.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> n = 3\n<strong>Output:</strong> 3\n<strong>Explanation:</strong> Initially, n = 3.\n3 is the smallest value n will take on.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>2 &lt;= n &lt;= 10<sup>5</sup></code></li>\n</ul>\n",
            "translatedTitle": "使用质因数之和替换后可以取到的最小值",
            "translatedContent": "<p>给你一个正整数 <code>n</code> 。</p>\n\n<p>请你将 <code>n</code> 的值替换为 <code>n</code> 的 <strong>质因数</strong> 之和，重复这一过程。</p>\n\n<ul>\n\t<li>注意，如果 <code>n</code> 能够被某个质因数多次整除，则在求和时，应当包含这个质因数同样次数。</li>\n</ul>\n\n<p>返回<em> </em><code>n</code><em> </em>可以取到的最小值。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre><strong>输入：</strong>n = 15\n<strong>输出：</strong>5\n<strong>解释：</strong>最开始，n = 15 。\n15 = 3 * 5 ，所以 n 替换为 3 + 5 = 8 。\n8 = 2 * 2 * 2 ，所以 n 替换为 2 + 2 + 2 = 6 。\n6 = 2 * 3 ，所以 n 替换为 2 + 3 = 5 。\n5 是 n 可以取到的最小值。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre><strong>输入：</strong>n = 3\n<strong>输出：</strong>3\n<strong>解释：</strong>最开始，n = 3 。\n3 是 n 可以取到的最小值。</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>2 &lt;= n &lt;= 10<sup>5</sup></code></li>\n</ul>\n",
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                "Every time you replace n, it will become smaller until it is a prime number, where it will keep the same value each time you replace it.",
                "n decreases logarithmically, allowing you to simulate the process.",
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