leetcode-problemset/leetcode-cn/originData/smallest-range-ii.json

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            "title": "Smallest Range II",
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            "content": "<p>You are given an integer array <code>nums</code> and an integer <code>k</code>.</p>\n\n<p>For each index <code>i</code> where <code>0 &lt;= i &lt; nums.length</code>, change <code>nums[i]</code> to be either <code>nums[i] + k</code> or <code>nums[i] - k</code>.</p>\n\n<p>The <strong>score</strong> of <code>nums</code> is the difference between the maximum and minimum elements in <code>nums</code>.</p>\n\n<p>Return <em>the minimum <strong>score</strong> of </em><code>nums</code><em> after changing the values at each index</em>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1], k = 0\n<strong>Output:</strong> 0\n<strong>Explanation:</strong> The score is max(nums) - min(nums) = 1 - 1 = 0.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [0,10], k = 2\n<strong>Output:</strong> 6\n<strong>Explanation:</strong> Change nums to be [2, 8]. The score is max(nums) - min(nums) = 8 - 2 = 6.\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,3,6], k = 3\n<strong>Output:</strong> 3\n<strong>Explanation:</strong> Change nums to be [4, 6, 3]. The score is max(nums) - min(nums) = 6 - 3 = 3.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 10<sup>4</sup></code></li>\n\t<li><code>0 &lt;= nums[i] &lt;= 10<sup>4</sup></code></li>\n\t<li><code>0 &lt;= k &lt;= 10<sup>4</sup></code></li>\n</ul>\n",
            "translatedTitle": "最小差值 II",
            "translatedContent": "<p>给你一个整数数组 <code>nums</code>，和一个整数&nbsp;<code>k</code> 。</p>\n\n<p>对于每个下标 <code>i</code>（<code>0 &lt;= i &lt; nums.length</code>），将 <code>nums[i]</code> 变成<strong> </strong> <code>nums[i] + k</code> 或 <code>nums[i] - k</code> 。</p>\n\n<p><code>nums</code> 的 <strong>分数</strong> 是 <code>nums</code> 中最大元素和最小元素的差值。</p>\n\n<p>在更改每个下标对应的值之后，返回 <code>nums</code> 的最小 <strong>分数</strong> 。</p>\n\n<p>&nbsp;</p>\n\n<ol>\n</ol>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [1], k = 0\n<strong>输出：</strong>0\n<strong>解释：</strong>分数 = max(nums) - min(nums) = 1 - 1 = 0 。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [0,10], k = 2\n<strong>输出：</strong>6\n<strong>解释：</strong>将数组变为 [2, 8] 。分数 = max(nums) - min(nums) = 8 - 2 = 6 。\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [1,3,6], k = 3\n<strong>输出：</strong>3\n<strong>解释：</strong>将数组变为 [4, 6, 3] 。分数 = max(nums) - min(nums) = 6 - 3 = 3 。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 10<sup>4</sup></code></li>\n\t<li><code>0 &lt;= nums[i] &lt;= 10<sup>4</sup></code></li>\n\t<li><code>0 &lt;= k &lt;= 10<sup>4</sup></code></li>\n</ul>\n",
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