leetcode-problemset/leetcode-cn/originData/put-marbles-in-bags.json

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            "questionId": "2681",
            "questionFrontendId": "2551",
            "categoryTitle": "Algorithms",
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            "title": "Put Marbles in Bags",
            "titleSlug": "put-marbles-in-bags",
            "content": "<p>You have <code>k</code> bags. You are given a <strong>0-indexed</strong> integer array <code>weights</code> where <code>weights[i]</code> is the weight of the <code>i<sup>th</sup></code> marble. You are also given the integer <code>k.</code></p>\n\n<p>Divide the marbles into the <code>k</code> bags according to the following rules:</p>\n\n<ul>\n\t<li>No bag is empty.</li>\n\t<li>If the <code>i<sup>th</sup></code> marble and <code>j<sup>th</sup></code> marble are in a bag, then all marbles with an index between the <code>i<sup>th</sup></code> and <code>j<sup>th</sup></code> indices should also be in that same bag.</li>\n\t<li>If a bag consists of all the marbles with an index from <code>i</code> to <code>j</code> inclusively, then the cost of the bag is <code>weights[i] + weights[j]</code>.</li>\n</ul>\n\n<p>The <strong>score</strong> after distributing the marbles is the sum of the costs of all the <code>k</code> bags.</p>\n\n<p>Return <em>the <strong>difference</strong> between the <strong>maximum</strong> and <strong>minimum</strong> scores among marble distributions</em>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> weights = [1,3,5,1], k = 2\n<strong>Output:</strong> 4\n<strong>Explanation:</strong> \nThe distribution [1],[3,5,1] results in the minimal score of (1+1) + (3+1) = 6. \nThe distribution [1,3],[5,1], results in the maximal score of (1+3) + (5+1) = 10. \nThus, we return their difference 10 - 6 = 4.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> weights = [1, 3], k = 2\n<strong>Output:</strong> 0\n<strong>Explanation:</strong> The only distribution possible is [1],[3]. \nSince both the maximal and minimal score are the same, we return 0.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= k &lt;= weights.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= weights[i] &lt;= 10<sup>9</sup></code></li>\n</ul>\n",
            "translatedTitle": "将珠子放入背包中",
            "translatedContent": "<p>你有&nbsp;<code>k</code>&nbsp;个背包。给你一个下标从 <strong>0</strong>&nbsp;开始的整数数组&nbsp;<code>weights</code>&nbsp;，其中&nbsp;<code>weights[i]</code>&nbsp;是第&nbsp;<code>i</code>&nbsp;个珠子的重量。同时给你整数 <code>k</code>&nbsp;。</p>\n\n<p>请你按照如下规则将所有的珠子放进&nbsp;<code>k</code>&nbsp;个背包。</p>\n\n<ul>\n\t<li>没有背包是空的。</li>\n\t<li>如果第&nbsp;<code>i</code>&nbsp;个珠子和第&nbsp;<code>j</code>&nbsp;个珠子在同一个背包里，那么下标在&nbsp;<code>i</code>&nbsp;到&nbsp;<code>j</code>&nbsp;之间的所有珠子都必须在这同一个背包中。</li>\n\t<li>如果一个背包有下标从&nbsp;<code>i</code>&nbsp;到&nbsp;<code>j</code>&nbsp;的所有珠子，那么这个背包的价格是&nbsp;<code>weights[i] + weights[j]</code>&nbsp;。</li>\n</ul>\n\n<p>一个珠子分配方案的 <strong>分数</strong>&nbsp;是所有 <code>k</code>&nbsp;个背包的价格之和。</p>\n\n<p>请你返回所有分配方案中，<strong>最大分数</strong>&nbsp;与 <strong>最小分数</strong>&nbsp;的 <strong>差值</strong>&nbsp;为多少。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre><b>输入：</b>weights = [1,3,5,1], k = 2\n<b>输出：</b>4\n<b>解释：</b>\n分配方案 [1],[3,5,1] 得到最小得分 (1+1) + (3+1) = 6 。\n分配方案 [1,3],[5,1] 得到最大得分 (1+3) + (5+1) = 10 。\n所以差值为 10 - 6 = 4 。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre><b>输入：</b>weights = [1, 3], k = 2\n<b>输出：</b>0\n<b>解释：</b>唯一的分配方案为 [1],[3] 。\n最大最小得分相等，所以返回 0 。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= k &lt;= weights.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= weights[i] &lt;= 10<sup>9</sup></code></li>\n</ul>\n",
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