leetcode-problemset/leetcode-cn/originData/project-employees-i.json

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            "title": "Project Employees I",
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            "content": "<p>Table: <code>Project</code></p>\n\n<pre>\n+-------------+---------+\n| Column Name | Type    |\n+-------------+---------+\n| project_id  | int     |\n| employee_id | int     |\n+-------------+---------+\n(project_id, employee_id) is the primary key of this table.\nemployee_id is a foreign key to <code>Employee</code> table.\nEach row of this table indicates that the employee with employee_id is working on the project with project_id.\n</pre>\n\n<p>&nbsp;</p>\n\n<p>Table: <code>Employee</code></p>\n\n<pre>\n+------------------+---------+\n| Column Name      | Type    |\n+------------------+---------+\n| employee_id      | int     |\n| name             | varchar |\n| experience_years | int     |\n+------------------+---------+\nemployee_id is the primary key of this table. It&#39;s guaranteed that experience_years is not NULL.\nEach row of this table contains information about one employee.\n</pre>\n\n<p>&nbsp;</p>\n\n<p>Write an SQL query that reports the <strong>average</strong> experience years of all the employees for each project, <strong>rounded to 2 digits</strong>.</p>\n\n<p>Return the result table in <strong>any order</strong>.</p>\n\n<p>The query result format is in the following example.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> \nProject table:\n+-------------+-------------+\n| project_id  | employee_id |\n+-------------+-------------+\n| 1           | 1           |\n| 1           | 2           |\n| 1           | 3           |\n| 2           | 1           |\n| 2           | 4           |\n+-------------+-------------+\nEmployee table:\n+-------------+--------+------------------+\n| employee_id | name   | experience_years |\n+-------------+--------+------------------+\n| 1           | Khaled | 3                |\n| 2           | Ali    | 2                |\n| 3           | John   | 1                |\n| 4           | Doe    | 2                |\n+-------------+--------+------------------+\n<strong>Output:</strong> \n+-------------+---------------+\n| project_id  | average_years |\n+-------------+---------------+\n| 1           | 2.00          |\n| 2           | 2.50          |\n+-------------+---------------+\n<strong>Explanation:</strong> The average experience years for the first project is (3 + 2 + 1) / 3 = 2.00 and for the second project is (3 + 2) / 2 = 2.50\n</pre>\n",
            "translatedTitle": "项目员工 I",
            "translatedContent": "<p>项目表&nbsp;<code>Project</code>：&nbsp;</p>\n\n<pre>\n+-------------+---------+\n| Column Name | Type    |\n+-------------+---------+\n| project_id  | int     |\n| employee_id | int     |\n+-------------+---------+\n主键为 (project_id, employee_id)。\nemployee_id 是员工表 <code>Employee 表的外键。</code>\n</pre>\n\n<p>员工表&nbsp;<code>Employee</code>：</p>\n\n<pre>\n+------------------+---------+\n| Column Name      | Type    |\n+------------------+---------+\n| employee_id      | int     |\n| name             | varchar |\n| experience_years | int     |\n+------------------+---------+\n主键是 employee_id。\n</pre>\n\n<p>&nbsp;</p>\n\n<p>请写一个 SQL&nbsp;语句，查询每一个项目中员工的&nbsp;<strong>平均&nbsp;</strong>工作年限，<strong>精确到小数点后两位</strong>。</p>\n\n<p>查询结果的格式如下：</p>\n\n<pre>\nProject 表：\n+-------------+-------------+\n| project_id  | employee_id |\n+-------------+-------------+\n| 1           | 1           |\n| 1           | 2           |\n| 1           | 3           |\n| 2           | 1           |\n| 2           | 4           |\n+-------------+-------------+\n\nEmployee 表：\n+-------------+--------+------------------+\n| employee_id | name   | experience_years |\n+-------------+--------+------------------+\n| 1           | Khaled | 3                |\n| 2           | Ali    | 2                |\n| 3           | John   | 1                |\n| 4           | Doe    | 2                |\n+-------------+--------+------------------+\n\nResult 表：\n+-------------+---------------+\n| project_id  | average_years |\n+-------------+---------------+\n| 1           | 2.00          |\n| 2           | 2.50          |\n+-------------+---------------+\n第一个项目中，员工的平均工作年限是 (3 + 2 + 1) / 3 = 2.00；第二个项目中，员工的平均工作年限是 (3 + 2) / 2 = 2.50\n</pre>\n",
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                    "code": "import pandas as pd\n\ndef project_employees_i(project: pd.DataFrame, employee: pd.DataFrame) -> pd.DataFrame:\n    ",
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            "sampleTestCase": "{\"headers\":{\"Project\":[\"project_id\",\"employee_id\"],\"Employee\":[\"employee_id\",\"name\",\"experience_years\"]},\"rows\":{\"Project\":[[1,1],[1,2],[1,3],[2,1],[2,4]],\"Employee\":[[1,\"Khaled\",3],[2,\"Ali\",2],[3,\"John\",1],[4,\"Doe\",2]]}}",
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                "Create table If Not Exists Project (project_id int, employee_id int)",
                "Create table If Not Exists Employee (employee_id int, name varchar(10), experience_years int)",
                "Truncate table Project",
                "insert into Project (project_id, employee_id) values ('1', '1')",
                "insert into Project (project_id, employee_id) values ('1', '2')",
                "insert into Project (project_id, employee_id) values ('1', '3')",
                "insert into Project (project_id, employee_id) values ('2', '1')",
                "insert into Project (project_id, employee_id) values ('2', '4')",
                "Truncate table Employee",
                "insert into Employee (employee_id, name, experience_years) values ('1', 'Khaled', '3')",
                "insert into Employee (employee_id, name, experience_years) values ('2', 'Ali', '2')",
                "insert into Employee (employee_id, name, experience_years) values ('3', 'John', '1')",
                "insert into Employee (employee_id, name, experience_years) values ('4', 'Doe', '2')"
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