leetcode-problemset/leetcode-cn/originData/profitable-schemes.json

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            "categoryTitle": "Algorithms",
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            "title": "Profitable Schemes",
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            "content": "<p>There is a group of <code>n</code> members, and a list of various crimes they could commit. The <code>i<sup>th</sup></code> crime generates a <code>profit[i]</code> and requires <code>group[i]</code> members to participate in it. If a member participates in one crime, that member can&#39;t participate in another crime.</p>\n\n<p>Let&#39;s call a <strong>profitable scheme</strong> any subset of these crimes that generates at least <code>minProfit</code> profit, and the total number of members participating in that subset of crimes is at most <code>n</code>.</p>\n\n<p>Return the number of schemes that can be chosen. Since the answer may be very large, <strong>return it modulo</strong> <code>10<sup>9</sup> + 7</code>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> n = 5, minProfit = 3, group = [2,2], profit = [2,3]\n<strong>Output:</strong> 2\n<strong>Explanation:</strong> To make a profit of at least 3, the group could either commit crimes 0 and 1, or just crime 1.\nIn total, there are 2 schemes.</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> n = 10, minProfit = 5, group = [2,3,5], profit = [6,7,8]\n<strong>Output:</strong> 7\n<strong>Explanation:</strong> To make a profit of at least 5, the group could commit any crimes, as long as they commit one.\nThere are 7 possible schemes: (0), (1), (2), (0,1), (0,2), (1,2), and (0,1,2).</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= n &lt;= 100</code></li>\n\t<li><code>0 &lt;= minProfit &lt;= 100</code></li>\n\t<li><code>1 &lt;= group.length &lt;= 100</code></li>\n\t<li><code>1 &lt;= group[i] &lt;= 100</code></li>\n\t<li><code>profit.length == group.length</code></li>\n\t<li><code>0 &lt;= profit[i] &lt;= 100</code></li>\n</ul>\n",
            "translatedTitle": "盈利计划",
            "translatedContent": "<p>集团里有 <code>n</code> 名员工，他们可以完成各种各样的工作创造利润。</p>\n\n<p>第 <code>i</code> 种工作会产生 <code>profit[i]</code> 的利润，它要求 <code>group[i]</code> 名成员共同参与。如果成员参与了其中一项工作，就不能参与另一项工作。</p>\n\n<p>工作的任何至少产生 <code>minProfit</code> 利润的子集称为 <strong>盈利计划</strong> 。并且工作的成员总数最多为 <code>n</code> 。</p>\n\n<p>有多少种计划可以选择？因为答案很大，所以<strong> 返回结果模 </strong><code>10^9 + 7</code><strong> 的值</strong>。</p>\n\n<div class=\"original__bRMd\">\n<div>\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>n = 5, minProfit = 3, group = [2,2], profit = [2,3]\n<strong>输出：</strong>2\n<strong>解释：</strong>至少产生 3 的利润，该集团可以完成工作 0 和工作 1 ，或仅完成工作 1 。\n总的来说，有两种计划。</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>n = 10, minProfit = 5, group = [2,3,5], profit = [6,7,8]\n<strong>输出：</strong>7\n<strong>解释：</strong>至少产生 5 的利润，只要完成其中一种工作就行，所以该集团可以完成任何工作。\n有 7 种可能的计划：(0)，(1)，(2)，(0,1)，(0,2)，(1,2)，以及 (0,1,2) 。</pre>\n</div>\n</div>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 <= n <= 100</code></li>\n\t<li><code>0 <= minProfit <= 100</code></li>\n\t<li><code>1 <= group.length <= 100</code></li>\n\t<li><code>1 <= group[i] <= 100</code></li>\n\t<li><code>profit.length == group.length</code></li>\n\t<li><code>0 <= profit[i] <= 100</code></li>\n</ul>\n",
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                    "code": "class Solution {\npublic:\n    int profitableSchemes(int n, int minProfit, vector<int>& group, vector<int>& profit) {\n\n    }\n};",
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                    "code": "class Solution(object):\n    def profitableSchemes(self, n, minProfit, group, profit):\n        \"\"\"\n        :type n: int\n        :type minProfit: int\n        :type group: List[int]\n        :type profit: List[int]\n        :rtype: int\n        \"\"\"",
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