leetcode-problemset/leetcode-cn/originData/pairs-with-sum-lcci.json

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        "question": {
            "questionId": "1000042",
            "questionFrontendId": "面试题 16.24",
            "categoryTitle": "LCCI",
            "boundTopicId": 99786,
            "title": "Pairs With Sum LCCI",
            "titleSlug": "pairs-with-sum-lcci",
            "content": "<p>Design an algorithm to find all pairs of integers within an array which sum to a specified value.</p>\r\n\r\n<p><strong>Example 1:</strong></p>\r\n\r\n<pre>\r\n<strong>Input:</strong> nums = [5,6,5], target = 11\r\n<strong>Output: </strong>[[5,6]]</pre>\r\n\r\n<p><strong>Example 2:</strong></p>\r\n\r\n<pre>\r\n<strong>Input:</strong> nums = [5,6,5,6], target = 11\r\n<strong>Output: </strong>[[5,6],[5,6]]</pre>\r\n\r\n<p><strong>Note: </strong></p>\r\n\r\n<ul>\r\n\t<li><code>nums.length &lt;= 100000</code></li>\r\n\t<li><code>-10^5 &lt;= nums[i], target &lt;= 10^5</code></li>\r\n</ul>\r\n",
            "translatedTitle": "数对和",
            "translatedContent": "<p>设计一个算法，找出数组中两数之和为指定值的所有整数对。一个数只能属于一个数对。</p>\n\n<p><strong>示例 1:</strong></p>\n\n<pre>\n<strong>输入:</strong> nums = [5,6,5], target = 11\n<strong>输出: </strong>[[5,6]]</pre>\n\n<p><strong>示例 2:</strong></p>\n\n<pre>\n<strong>输入:</strong> nums = [5,6,5,6], target = 11\n<strong>输出: </strong>[[5,6],[5,6]]</pre>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>nums.length &lt;= 100000</code></li>\n\t<li><code>-10^5 &lt;= nums[i], target &lt;= 10^5</code></li>\n</ul>\n",
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                    "name": "Array",
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                    "name": "Hash Table",
                    "slug": "hash-table",
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                    "lang": "C++",
                    "langSlug": "cpp",
                    "code": "class Solution {\npublic:\n    vector<vector<int>> pairSums(vector<int>& nums, int target) {\n\n    }\n};",
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                },
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                    "code": "class Solution(object):\n    def pairSums(self, nums, target):\n        \"\"\"\n        :type nums: List[int]\n        :type target: int\n        :rtype: List[List[int]]\n        \"\"\"",
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                    "code": "\n\n/**\n * Return an array of arrays of size *returnSize.\n * The sizes of the arrays are returned as *returnColumnSizes array.\n * Note: Both returned array and *columnSizes array must be malloced, assume caller calls free().\n */\nint** pairSums(int* nums, int numsSize, int target, int* returnSize, int** returnColumnSizes){\n\n}\n",
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                    "code": "public class Solution {\n    public IList<IList<int>> PairSums(int[] nums, int target) {\n\n    }\n}",
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                    "code": "/**\n * @param {number[]} nums\n * @param {number} target\n * @return {number[][]}\n */\nvar pairSums = function(nums, target) {\n\n};",
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                    "code": "class Solution {\n\n    /**\n     * @param Integer[] $nums\n     * @param Integer $target\n     * @return Integer[][]\n     */\n    function pairSums($nums, $target) {\n\n    }\n}",
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                    "code": "class Solution {\n    fun pairSums(nums: IntArray, target: Int): List<List<Int>> {\n\n    }\n}",
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                    "code": "defmodule Solution do\n  @spec pair_sums(nums :: [integer], target :: integer) :: [[integer]]\n  def pair_sums(nums, target) do\n\n  end\nend",
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            "hints": [
                "从蛮力解法开始。运行复杂度是什么？解决这个问题的最佳时间是什么？",
                "我们可以用散列表使它更快吗?",
                "如果数组有序呢？",
                "如果我们对数组进行排序，那么就可以对数字进行重复的二进制搜索。如果数组是有序的呢？我们能否在O(N)时间和O(1)空间中求解这个问题？"
            ],
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