leetcode-problemset/leetcode-cn/originData/number-of-subarrays-with-lcm-equal-to-k.json

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            "questionId": "2557",
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            "categoryTitle": "Algorithms",
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            "title": "Number of Subarrays With LCM Equal to K",
            "titleSlug": "number-of-subarrays-with-lcm-equal-to-k",
            "content": "<p>Given an integer array <code>nums</code> and an integer <code>k</code>, return <em>the number of <strong>subarrays</strong> of </em><code>nums</code><em> where the least common multiple of the subarray&#39;s elements is </em><code>k</code>.</p>\n\n<p>A <strong>subarray</strong> is a contiguous non-empty sequence of elements within an array.</p>\n\n<p>The <strong>least common multiple of an array</strong> is the smallest positive integer that is divisible by all the array elements.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [3,6,2,7,1], k = 6\n<strong>Output:</strong> 4\n<strong>Explanation:</strong> The subarrays of nums where 6 is the least common multiple of all the subarray&#39;s elements are:\n- [<u><strong>3</strong></u>,<u><strong>6</strong></u>,2,7,1]\n- [<u><strong>3</strong></u>,<u><strong>6</strong></u>,<u><strong>2</strong></u>,7,1]\n- [3,<u><strong>6</strong></u>,2,7,1]\n- [3,<u><strong>6</strong></u>,<u><strong>2</strong></u>,7,1]\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [3], k = 2\n<strong>Output:</strong> 0\n<strong>Explanation:</strong> There are no subarrays of nums where 2 is the least common multiple of all the subarray&#39;s elements.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 1000</code></li>\n\t<li><code>1 &lt;= nums[i], k &lt;= 1000</code></li>\n</ul>\n",
            "translatedTitle": "最小公倍数为 K 的子数组数目",
            "translatedContent": "<p>给你一个整数数组 <code>nums</code> 和一个整数 <code>k</code> ，请你统计并返回 <code>nums</code> 的 <strong>子数组</strong> 中满足 <em>元素最小公倍数为 <code>k</code> </em>的子数组数目。</p>\n\n<p><strong>子数组</strong> 是数组中一个连续非空的元素序列。</p>\n\n<p><strong>数组的最小公倍数</strong> 是可被所有数组元素整除的最小正整数。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1 ：</strong></p>\n\n<pre><strong>输入：</strong>nums = [3,6,2,7,1], k = 6\n<strong>输出：</strong>4\n<strong>解释：</strong>以 6 为最小公倍数的子数组是：\n- [<em><strong>3</strong></em>,<em><strong>6</strong></em>,2,7,1]\n- [<em><strong>3</strong></em>,<em><strong>6</strong></em>,<em><strong>2</strong></em>,7,1]\n- [3,<em><strong>6</strong></em>,2,7,1]\n- [3,<em><strong>6</strong></em>,<em><strong>2</strong></em>,7,1]\n</pre>\n\n<p><strong>示例 2 ：</strong></p>\n\n<pre><strong>输入：</strong>nums = [3], k = 2\n<strong>输出：</strong>0\n<strong>解释：</strong>不存在以 2 为最小公倍数的子数组。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 1000</code></li>\n\t<li><code>1 &lt;= nums[i], k &lt;= 1000</code></li>\n</ul>\n",
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                    "code": "class Solution {\npublic:\n    int subarrayLCM(vector<int>& nums, int k) {\n        \n    }\n};",
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                    "code": "class Solution(object):\n    def subarrayLCM(self, nums, k):\n        \"\"\"\n        :type nums: List[int]\n        :type k: int\n        :rtype: int\n        \"\"\"",
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                    "code": "# @param {Integer[]} nums\n# @param {Integer} k\n# @return {Integer}\ndef subarray_lcm(nums, k)\n\nend",
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            "hints": [
                "The constraints on nums.length are small. It is possible to check every subarray.",
                "To calculate LCM, you can use a built-in function or the formula lcm(a, b) = a * b / gcd(a, b).",
                "As you calculate the LCM of more numbers, it can only become greater. Once it becomes greater than k, you know that any larger subarrays containing all the current elements will not work."
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