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"categoryTitle": "Algorithms",
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"title": "Number of Pairs Satisfying Inequality",
"titleSlug": "number-of-pairs-satisfying-inequality",
"content": "<p>You are given two <strong>0-indexed</strong> integer arrays <code>nums1</code> and <code>nums2</code>, each of size <code>n</code>, and an integer <code>diff</code>. Find the number of <strong>pairs</strong> <code>(i, j)</code> such that:</p>\n\n<ul>\n\t<li><code>0 &lt;= i &lt; j &lt;= n - 1</code> <strong>and</strong></li>\n\t<li><code>nums1[i] - nums1[j] &lt;= nums2[i] - nums2[j] + diff</code>.</li>\n</ul>\n\n<p>Return<em> the <strong>number of pairs</strong> that satisfy the conditions.</em></p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums1 = [3,2,5], nums2 = [2,2,1], diff = 1\n<strong>Output:</strong> 3\n<strong>Explanation:</strong>\nThere are 3 pairs that satisfy the conditions:\n1. i = 0, j = 1: 3 - 2 &lt;= 2 - 2 + 1. Since i &lt; j and 1 &lt;= 1, this pair satisfies the conditions.\n2. i = 0, j = 2: 3 - 5 &lt;= 2 - 1 + 1. Since i &lt; j and -2 &lt;= 2, this pair satisfies the conditions.\n3. i = 1, j = 2: 2 - 5 &lt;= 2 - 1 + 1. Since i &lt; j and -3 &lt;= 2, this pair satisfies the conditions.\nTherefore, we return 3.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums1 = [3,-1], nums2 = [-2,2], diff = -1\n<strong>Output:</strong> 0\n<strong>Explanation:</strong>\nSince there does not exist any pair that satisfies the conditions, we return 0.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>n == nums1.length == nums2.length</code></li>\n\t<li><code>2 &lt;= n &lt;= 10<sup>5</sup></code></li>\n\t<li><code>-10<sup>4</sup> &lt;= nums1[i], nums2[i] &lt;= 10<sup>4</sup></code></li>\n\t<li><code>-10<sup>4</sup> &lt;= diff &lt;= 10<sup>4</sup></code></li>\n</ul>\n",
"translatedTitle": "满足不等式的数对数目",
"translatedContent": "<p>给你两个下标从 <strong>0</strong>&nbsp;开始的整数数组&nbsp;<code>nums1</code> 和&nbsp;<code>nums2</code>&nbsp;,两个数组的大小都为&nbsp;<code>n</code>&nbsp;,同时给你一个整数&nbsp;<code>diff</code>&nbsp;,统计满足以下条件的&nbsp;<strong>数对&nbsp;</strong><code>(i, j)</code>&nbsp;</p>\n\n<ul>\n\t<li><code>0 &lt;= i &lt; j &lt;= n - 1</code>&nbsp;<b>且</b></li>\n\t<li><code>nums1[i] - nums1[j] &lt;= nums2[i] - nums2[j] + diff</code>.</li>\n</ul>\n\n<p>请你返回满足条件的 <strong>数对数目</strong>&nbsp;。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1</strong></p>\n\n<pre><b>输入:</b>nums1 = [3,2,5], nums2 = [2,2,1], diff = 1\n<b>输出:</b>3\n<strong>解释:</strong>\n总共有 3 个满足条件的数对:\n1. i = 0, j = 13 - 2 &lt;= 2 - 2 + 1 。因为 i &lt; j 且 1 &lt;= 1 ,这个数对满足条件。\n2. i = 0, j = 23 - 5 &lt;= 2 - 1 + 1 。因为 i &lt; j 且 -2 &lt;= 2 ,这个数对满足条件。\n3. i = 1, j = 22 - 5 &lt;= 2 - 1 + 1 。因为 i &lt; j 且 -3 &lt;= 2 ,这个数对满足条件。\n所以我们返回 3 。\n</pre>\n\n<p><strong>示例 2</strong></p>\n\n<pre><b>输入:</b>nums1 = [3,-1], nums2 = [-2,2], diff = -1\n<b>输出:</b>0\n<strong>解释:</strong>\n没有满足条件的任何数对所以我们返回 0 。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>n == nums1.length == nums2.length</code></li>\n\t<li><code>2 &lt;= n &lt;= 10<sup>5</sup></code></li>\n\t<li><code>-10<sup>4</sup> &lt;= nums1[i], nums2[i] &lt;= 10<sup>4</sup></code></li>\n\t<li><code>-10<sup>4</sup> &lt;= diff &lt;= 10<sup>4</sup></code></li>\n</ul>\n",
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