leetcode-problemset/leetcode-cn/originData/n-th-tribonacci-number.json

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            "questionId": "1236",
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            "title": "N-th Tribonacci Number",
            "titleSlug": "n-th-tribonacci-number",
            "content": "<p>The Tribonacci sequence T<sub>n</sub> is defined as follows:&nbsp;</p>\r\n\r\n<p>T<sub>0</sub> = 0, T<sub>1</sub> = 1, T<sub>2</sub> = 1, and T<sub>n+3</sub> = T<sub>n</sub> + T<sub>n+1</sub> + T<sub>n+2</sub> for n &gt;= 0.</p>\r\n\r\n<p>Given <code>n</code>, return the value of T<sub>n</sub>.</p>\r\n\r\n<p>&nbsp;</p>\r\n<p><strong class=\"example\">Example 1:</strong></p>\r\n\r\n<pre>\r\n<strong>Input:</strong> n = 4\r\n<strong>Output:</strong> 4\r\n<strong>Explanation:</strong>\r\nT_3 = 0 + 1 + 1 = 2\r\nT_4 = 1 + 1 + 2 = 4\r\n</pre>\r\n\r\n<p><strong class=\"example\">Example 2:</strong></p>\r\n\r\n<pre>\r\n<strong>Input:</strong> n = 25\r\n<strong>Output:</strong> 1389537\r\n</pre>\r\n\r\n<p>&nbsp;</p>\r\n<p><strong>Constraints:</strong></p>\r\n\r\n<ul>\r\n\t<li><code>0 &lt;= n &lt;= 37</code></li>\r\n\t<li>The answer is guaranteed to fit within a 32-bit integer, ie. <code>answer &lt;= 2^31 - 1</code>.</li>\r\n</ul>",
            "translatedTitle": "第 N 个泰波那契数",
            "translatedContent": "<p>泰波那契序列&nbsp;T<sub>n</sub>&nbsp;定义如下：&nbsp;</p>\n\n<p>T<sub>0</sub> = 0, T<sub>1</sub> = 1, T<sub>2</sub> = 1, 且在 n &gt;= 0&nbsp;的条件下 T<sub>n+3</sub> = T<sub>n</sub> + T<sub>n+1</sub> + T<sub>n+2</sub></p>\n\n<p>给你整数&nbsp;<code>n</code>，请返回第 n 个泰波那契数&nbsp;T<sub>n </sub>的值。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre><strong>输入：</strong>n = 4\n<strong>输出：</strong>4\n<strong>解释：</strong>\nT_3 = 0 + 1 + 1 = 2\nT_4 = 1 + 1 + 2 = 4\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre><strong>输入：</strong>n = 25\n<strong>输出：</strong>1389537\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>0 &lt;= n &lt;= 37</code></li>\n\t<li>答案保证是一个 32 位整数，即&nbsp;<code>answer &lt;= 2^31 - 1</code>。</li>\n</ul>\n",
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                "Make an array F of length 38, and set F[0] = 0, F[1] = F[2] = 1.",
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