leetcode-problemset/leetcode-cn/originData/minimum-number-of-days-to-eat-n-oranges.json

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            "questionId": "1676",
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            "title": "Minimum Number of Days to Eat N Oranges",
            "titleSlug": "minimum-number-of-days-to-eat-n-oranges",
            "content": "<p>There are <code>n</code> oranges in the kitchen and you decided to eat some of these oranges every day as follows:</p>\n\n<ul>\n\t<li>Eat one orange.</li>\n\t<li>If the number of remaining oranges <code>n</code> is divisible by <code>2</code> then you can eat <code>n / 2</code> oranges.</li>\n\t<li>If the number of remaining oranges <code>n</code> is divisible by <code>3</code> then you can eat <code>2 * (n / 3)</code> oranges.</li>\n</ul>\n\n<p>You can only choose one of the actions per day.</p>\n\n<p>Given the integer <code>n</code>, return <em>the minimum number of days to eat</em> <code>n</code> <em>oranges</em>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> n = 10\n<strong>Output:</strong> 4\n<strong>Explanation:</strong> You have 10 oranges.\nDay 1: Eat 1 orange,  10 - 1 = 9.  \nDay 2: Eat 6 oranges, 9 - 2*(9/3) = 9 - 6 = 3. (Since 9 is divisible by 3)\nDay 3: Eat 2 oranges, 3 - 2*(3/3) = 3 - 2 = 1. \nDay 4: Eat the last orange  1 - 1  = 0.\nYou need at least 4 days to eat the 10 oranges.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> n = 6\n<strong>Output:</strong> 3\n<strong>Explanation:</strong> You have 6 oranges.\nDay 1: Eat 3 oranges, 6 - 6/2 = 6 - 3 = 3. (Since 6 is divisible by 2).\nDay 2: Eat 2 oranges, 3 - 2*(3/3) = 3 - 2 = 1. (Since 3 is divisible by 3)\nDay 3: Eat the last orange  1 - 1  = 0.\nYou need at least 3 days to eat the 6 oranges.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= n &lt;= 2 * 10<sup>9</sup></code></li>\n</ul>\n",
            "translatedTitle": "吃掉 N 个橘子的最少天数",
            "translatedContent": "<p>厨房里总共有 <code>n</code>&nbsp;个橘子，你决定每一天选择如下方式之一吃这些橘子：</p>\n\n<ul>\n\t<li>吃掉一个橘子。</li>\n\t<li>如果剩余橘子数 <code>n</code>&nbsp;能被 2 整除，那么你可以吃掉 <code>n/2</code> 个橘子。</li>\n\t<li>如果剩余橘子数&nbsp;<code>n</code>&nbsp;能被 3 整除，那么你可以吃掉 <code>2*(n/3)</code> 个橘子。</li>\n</ul>\n\n<p>每天你只能从以上 3 种方案中选择一种方案。</p>\n\n<p>请你返回吃掉所有 <code>n</code>&nbsp;个橘子的最少天数。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre><strong>输入：</strong>n = 10\n<strong>输出：</strong>4\n<strong>解释：</strong>你总共有 10 个橘子。\n第 1 天：吃 1 个橘子，剩余橘子数 10 - 1 = 9。\n第 2 天：吃 6 个橘子，剩余橘子数 9 - 2*(9/3) = 9 - 6 = 3。（9 可以被 3 整除）\n第 3 天：吃 2 个橘子，剩余橘子数 3 - 2*(3/3) = 3 - 2 = 1。\n第 4 天：吃掉最后 1 个橘子，剩余橘子数 1 - 1 = 0。\n你需要至少 4 天吃掉 10 个橘子。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre><strong>输入：</strong>n = 6\n<strong>输出：</strong>3\n<strong>解释：</strong>你总共有 6 个橘子。\n第 1 天：吃 3 个橘子，剩余橘子数 6 - 6/2 = 6 - 3 = 3。（6 可以被 2 整除）\n第 2 天：吃 2 个橘子，剩余橘子数 3 - 2*(3/3) = 3 - 2 = 1。（3 可以被 3 整除）\n第 3 天：吃掉剩余 1 个橘子，剩余橘子数 1 - 1 = 0。\n你至少需要 3 天吃掉 6 个橘子。\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre><strong>输入：</strong>n = 1\n<strong>输出：</strong>1\n</pre>\n\n<p><strong>示例 4：</strong></p>\n\n<pre><strong>输入：</strong>n = 56\n<strong>输出：</strong>6\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= n &lt;= 2*10^9</code></li>\n</ul>\n",
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