leetcode-problemset/leetcode-cn/originData/minimum-cost-to-move-chips-to-the-same-position.json

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            "title": "Minimum Cost to Move Chips to The Same Position",
            "titleSlug": "minimum-cost-to-move-chips-to-the-same-position",
            "content": "<p>We have <code>n</code> chips, where the position of the <code>i<sup>th</sup></code> chip is <code>position[i]</code>.</p>\n\n<p>We need to move all the chips to <strong>the same position</strong>. In one step, we can change the position of the <code>i<sup>th</sup></code> chip from <code>position[i]</code> to:</p>\n\n<ul>\n\t<li><code>position[i] + 2</code> or <code>position[i] - 2</code> with <code>cost = 0</code>.</li>\n\t<li><code>position[i] + 1</code> or <code>position[i] - 1</code> with <code>cost = 1</code>.</li>\n</ul>\n\n<p>Return <em>the minimum cost</em> needed to move all the chips to the same position.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/08/15/chips_e1.jpg\" style=\"width: 750px; height: 217px;\" />\n<pre>\n<strong>Input:</strong> position = [1,2,3]\n<strong>Output:</strong> 1\n<strong>Explanation:</strong> First step: Move the chip at position 3 to position 1 with cost = 0.\nSecond step: Move the chip at position 2 to position 1 with cost = 1.\nTotal cost is 1.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/08/15/chip_e2.jpg\" style=\"width: 750px; height: 306px;\" />\n<pre>\n<strong>Input:</strong> position = [2,2,2,3,3]\n<strong>Output:</strong> 2\n<strong>Explanation:</strong> We can move the two chips at position  3 to position 2. Each move has cost = 1. The total cost = 2.\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> position = [1,1000000000]\n<strong>Output:</strong> 1\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= position.length &lt;= 100</code></li>\n\t<li><code>1 &lt;= position[i] &lt;= 10^9</code></li>\n</ul>\n",
            "translatedTitle": "玩筹码",
            "translatedContent": "<p>有&nbsp;<code>n</code>&nbsp;个筹码。第 <code>i</code> 个筹码的位置是<meta charset=\"UTF-8\" />&nbsp;<code>position[i]</code>&nbsp;。</p>\n\n<p>我们需要把所有筹码移到同一个位置。在一步中，我们可以将第 <code>i</code> 个筹码的位置从&nbsp;<code>position[i]</code>&nbsp;改变为:</p>\n\n<p><meta charset=\"UTF-8\" /></p>\n\n<ul>\n\t<li><code>position[i] + 2</code>&nbsp;或&nbsp;<code>position[i] - 2</code>&nbsp;，此时&nbsp;<code>cost = 0</code></li>\n\t<li><code>position[i] + 1</code>&nbsp;或&nbsp;<code>position[i] - 1</code>&nbsp;，此时&nbsp;<code>cost = 1</code></li>\n</ul>\n\n<p>返回将所有筹码移动到同一位置上所需要的 <em>最小代价</em> 。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<p><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/08/15/chips_e1.jpg\" style=\"height: 217px; width: 750px;\" /></p>\n\n<pre>\n<strong>输入：</strong>position = [1,2,3]\n<strong>输出：</strong>1\n<strong>解释：</strong>第一步:将位置3的筹码移动到位置1，成本为0。\n第二步:将位置2的筹码移动到位置1，成本= 1。\n总成本是1。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<p><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/08/15/chip_e2.jpg\" style=\"height: 306px; width: 750px;\" /></p>\n\n<pre>\n<strong>输入：</strong>position = [2,2,2,3,3]\n<strong>输出：</strong>2\n<strong>解释：</strong>我们可以把位置3的两个筹码移到位置2。每一步的成本为1。总成本= 2。\n</pre>\n\n<p><strong>示例 3:</strong></p>\n\n<pre>\n<strong>输入：</strong>position = [1,1000000000]\n<strong>输出：</strong>1\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= position.length &lt;= 100</code></li>\n\t<li><code>1 &lt;= position[i] &lt;= 10^9</code></li>\n</ul>\n",
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                "The first move keeps the parity of the element as it is.",
                "The second move changes the parity of the element.",
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