leetcode-problemset/leetcode-cn/originData/minimum-cost-to-make-array-equal.json

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            "title": "Minimum Cost to Make Array Equal",
            "titleSlug": "minimum-cost-to-make-array-equal",
            "content": "<p>You are given two <strong>0-indexed</strong> arrays <code>nums</code> and <code>cost</code> consisting each of <code>n</code> <strong>positive</strong> integers.</p>\n\n<p>You can do the following operation <strong>any</strong> number of times:</p>\n\n<ul>\n\t<li>Increase or decrease <strong>any</strong> element of the array <code>nums</code> by <code>1</code>.</li>\n</ul>\n\n<p>The cost of doing one operation on the <code>i<sup>th</sup></code> element is <code>cost[i]</code>.</p>\n\n<p>Return <em>the <strong>minimum</strong> total cost such that all the elements of the array </em><code>nums</code><em> become <strong>equal</strong></em>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,3,5,2], cost = [2,3,1,14]\n<strong>Output:</strong> 8\n<strong>Explanation:</strong> We can make all the elements equal to 2 in the following way:\n- Increase the 0<sup>th</sup> element one time. The cost is 2.\n- Decrease the 1<sup><span style=\"font-size: 10.8333px;\">st</span></sup> element one time. The cost is 3.\n- Decrease the 2<sup>nd</sup> element three times. The cost is 1 + 1 + 1 = 3.\nThe total cost is 2 + 3 + 3 = 8.\nIt can be shown that we cannot make the array equal with a smaller cost.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [2,2,2,2,2], cost = [4,2,8,1,3]\n<strong>Output:</strong> 0\n<strong>Explanation:</strong> All the elements are already equal, so no operations are needed.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>n == nums.length == cost.length</code></li>\n\t<li><code>1 &lt;= n &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= nums[i], cost[i] &lt;= 10<sup>6</sup></code></li>\n\t<li>Test cases are generated in a way that the output doesn&#39;t exceed&nbsp;2<sup>53</sup>-1</li>\n</ul>\n",
            "translatedTitle": "使数组相等的最小开销",
            "translatedContent": "<p>给你两个下标从 <strong>0</strong>&nbsp;开始的数组&nbsp;<code>nums</code> 和&nbsp;<code>cost</code>&nbsp;，分别包含&nbsp;<code>n</code>&nbsp;个&nbsp;<strong>正</strong>&nbsp;整数。</p>\n\n<p>你可以执行下面操作 <strong>任意</strong>&nbsp;次：</p>\n\n<ul>\n\t<li>将&nbsp;<code>nums</code>&nbsp;中 <strong>任意</strong>&nbsp;元素增加或者减小 <code>1</code>&nbsp;。</li>\n</ul>\n\n<p>对第 <code>i</code>&nbsp;个元素执行一次操作的开销是&nbsp;<code>cost[i]</code>&nbsp;。</p>\n\n<p>请你返回使 <code>nums</code>&nbsp;中所有元素 <strong>相等</strong>&nbsp;的 <strong>最少</strong>&nbsp;总开销。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<b>输入：</b>nums = [1,3,5,2], cost = [2,3,1,14]\n<b>输出：</b>8\n<b>解释：</b>我们可以执行以下操作使所有元素变为 2 ：\n- 增加第 0 个元素 1 次，开销为 2 。\n- 减小第 1 个元素 1 次，开销为 3 。\n- 减小第 2 个元素 3 次，开销为 1 + 1 + 1 = 3 。\n总开销为 2 + 3 + 3 = 8 。\n这是最小开销。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<b>输入：</b>nums = [2,2,2,2,2], cost = [4,2,8,1,3]\n<b>输出：</b>0\n<b>解释：</b>数组中所有元素已经全部相等，不需要执行额外的操作。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>n == nums.length == cost.length</code></li>\n\t<li><code>1 &lt;= n &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= nums[i], cost[i] &lt;= 10<sup>6</sup></code></li>\n\t<li>测试用例确保输出不超过 2<sup>53</sup>-1。</li>\n</ul>\n",
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