leetcode-problemset/leetcode-cn/originData/maximum-value-of-an-ordered-triplet-ii.json

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            "title": "Maximum Value of an Ordered Triplet II",
            "titleSlug": "maximum-value-of-an-ordered-triplet-ii",
            "content": "<p>You are given a <strong>0-indexed</strong> integer array <code>nums</code>.</p>\n\n<p>Return <em><strong>the maximum value over all triplets of indices</strong></em> <code>(i, j, k)</code> <em>such that</em> <code>i &lt; j &lt; k</code><em>. </em>If all such triplets have a negative value, return <code>0</code>.</p>\n\n<p>The <strong>value of a triplet of indices</strong> <code>(i, j, k)</code> is equal to <code>(nums[i] - nums[j]) * nums[k]</code>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [12,6,1,2,7]\n<strong>Output:</strong> 77\n<strong>Explanation:</strong> The value of the triplet (0, 2, 4) is (nums[0] - nums[2]) * nums[4] = 77.\nIt can be shown that there are no ordered triplets of indices with a value greater than 77. \n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,10,3,4,19]\n<strong>Output:</strong> 133\n<strong>Explanation:</strong> The value of the triplet (1, 2, 4) is (nums[1] - nums[2]) * nums[4] = 133.\nIt can be shown that there are no ordered triplets of indices with a value greater than 133.\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,2,3]\n<strong>Output:</strong> 0\n<strong>Explanation:</strong> The only ordered triplet of indices (0, 1, 2) has a negative value of (nums[0] - nums[1]) * nums[2] = -3. Hence, the answer would be 0.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>3 &lt;= nums.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= nums[i] &lt;= 10<sup>6</sup></code></li>\n</ul>\n",
            "translatedTitle": "有序三元组中的最大值 II",
            "translatedContent": "<p>给你一个下标从 <strong>0</strong> 开始的整数数组 <code>nums</code> 。</p>\n\n<p>请你从所有满足&nbsp;<code>i &lt; j &lt; k</code> 的下标三元组 <code>(i, j, k)</code> 中，找出并返回下标三元组的最大值。如果所有满足条件的三元组的值都是负数，则返回 <code>0</code> 。</p>\n\n<p><strong>下标三元组</strong> <code>(i, j, k)</code> 的值等于 <code>(nums[i] - nums[j]) * nums[k]</code> 。</p>\n\n<p>&nbsp;</p>\n\n<p><strong class=\"example\">示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [12,6,1,2,7]\n<strong>输出：</strong>77\n<strong>解释：</strong>下标三元组 (0, 2, 4) 的值是 (nums[0] - nums[2]) * nums[4] = 77 。\n可以证明不存在值大于 77 的有序下标三元组。\n</pre>\n\n<p><strong class=\"example\">示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [1,10,3,4,19]\n<strong>输出：</strong>133\n<strong>解释：</strong>下标三元组 (1, 2, 4) 的值是 (nums[1] - nums[2]) * nums[4] = 133 。\n可以证明不存在值大于 133 的有序下标三元组。 \n</pre>\n\n<p><strong class=\"example\">示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [1,2,3]\n<strong>输出：</strong>0\n<strong>解释：</strong>唯一的下标三元组 (0, 1, 2) 的值是一个负数，(nums[0] - nums[1]) * nums[2] = -3 。因此，答案是 0 。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>3 &lt;= nums.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= nums[i] &lt;= 10<sup>6</sup></code></li>\n</ul>\n",
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                "Preprocess the prefix maximum array, <code>prefix_max[i] = max(nums[0], nums[1], …, nums[i])</code> and the suffix maximum array, <code>suffix_max[i] = max(nums[i], nums[i + 1], …, nums[i - 1])</code>.",
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