leetcode-problemset/leetcode-cn/originData/maximum-score-from-performing-multiplication-operations.json

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            "title": "Maximum Score from Performing Multiplication Operations",
            "titleSlug": "maximum-score-from-performing-multiplication-operations",
            "content": "<p>You are given two <strong>0-indexed</strong> integer arrays <code>nums</code> and <code>multipliers</code><strong> </strong>of size <code>n</code> and <code>m</code> respectively, where <code>n &gt;= m</code>.</p>\n\n<p>You begin with a score of <code>0</code>. You want to perform <strong>exactly</strong> <code>m</code> operations. On the <code>i<sup>th</sup></code> operation (<strong>0-indexed</strong>) you will:</p>\n\n<ul>\n    <li>Choose one integer <code>x</code> from <strong>either the start or the end </strong>of the array <code>nums</code>.</li>\n    <li>Add <code>multipliers[i] * x</code> to your score.\n    <ul>\n        <li>Note that <code>multipliers[0]</code> corresponds to the first operation, <code>multipliers[1]</code> to the second operation, and so on.</li>\n    </ul>\n    </li>\n    <li>Remove <code>x</code> from <code>nums</code>.</li>\n</ul>\n\n<p>Return <em>the <strong>maximum</strong> score after performing </em><code>m</code> <em>operations.</em></p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,2,3], multipliers = [3,2,1]\n<strong>Output:</strong> 14\n<strong>Explanation:</strong>&nbsp;An optimal solution is as follows:\n- Choose from the end, [1,2,<strong><u>3</u></strong>], adding 3 * 3 = 9 to the score.\n- Choose from the end, [1,<strong><u>2</u></strong>], adding 2 * 2 = 4 to the score.\n- Choose from the end, [<strong><u>1</u></strong>], adding 1 * 1 = 1 to the score.\nThe total score is 9 + 4 + 1 = 14.</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [-5,-3,-3,-2,7,1], multipliers = [-10,-5,3,4,6]\n<strong>Output:</strong> 102\n<strong>Explanation: </strong>An optimal solution is as follows:\n- Choose from the start, [<u><strong>-5</strong></u>,-3,-3,-2,7,1], adding -5 * -10 = 50 to the score.\n- Choose from the start, [<strong><u>-3</u></strong>,-3,-2,7,1], adding -3 * -5 = 15 to the score.\n- Choose from the start, [<strong><u>-3</u></strong>,-2,7,1], adding -3 * 3 = -9 to the score.\n- Choose from the end, [-2,7,<strong><u>1</u></strong>], adding 1 * 4 = 4 to the score.\n- Choose from the end, [-2,<strong><u>7</u></strong>], adding 7 * 6 = 42 to the score. \nThe total score is 50 + 15 - 9 + 4 + 42 = 102.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>n == nums.length</code></li>\n\t<li><code>m == multipliers.length</code></li>\n\t<li><code>1 &lt;= m &lt;= 300</code></li>\n\t<li><code>m &lt;= n &lt;= 10<sup>5</sup></code><code> </code></li>\n\t<li><code>-1000 &lt;= nums[i], multipliers[i] &lt;= 1000</code></li>\n</ul>\n",
            "translatedTitle": "执行乘法运算的最大分数",
            "translatedContent": "<p>给你两个长度分别 <code>n</code> 和 <code>m</code> 的整数数组 <code>nums</code> 和 <code>multipliers</code><strong> </strong>，其中 <code>n &gt;= m</code> ，数组下标 <strong>从 1 开始</strong> 计数。</p>\n\n<p>初始时，你的分数为 <code>0</code> 。你需要执行恰好 <code>m</code> 步操作。在第 <code>i</code> 步操作（<strong>从 1 开始</strong> 计数）中，需要：</p>\n\n<ul>\n\t<li>选择数组 <code>nums</code> <strong>开头处或者末尾处</strong> 的整数 <code>x</code> 。</li>\n\t<li>你获得 <code>multipliers[i] * x</code> 分，并累加到你的分数中。</li>\n\t<li>将 <code>x</code> 从数组 <code>nums</code> 中移除。</li>\n</ul>\n\n<p>在执行<em> </em><code>m</code> 步操作后，返回 <strong>最大</strong> 分数<em>。</em></p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre><strong>输入：</strong>nums = [1,2,3], multipliers = [3,2,1]\n<strong>输出：</strong>14\n<strong>解释：</strong>一种最优解决方案如下：\n- 选择末尾处的整数 3 ，[1,2,<strong>3</strong>] ，得 3 * 3 = 9 分，累加到分数中。\n- 选择末尾处的整数 2 ，[1,<strong>2</strong>] ，得 2 * 2 = 4 分，累加到分数中。\n- 选择末尾处的整数 1 ，[<strong>1</strong>] ，得 1 * 1 = 1 分，累加到分数中。\n总分数为 9 + 4 + 1 = 14 。</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre><strong>输入：</strong>nums = [-5,-3,-3,-2,7,1], multipliers = [-10,-5,3,4,6]\n<strong>输出：</strong>102\n<strong>解释：</strong>一种最优解决方案如下：\n- 选择开头处的整数 -5 ，[<strong>-5</strong>,-3,-3,-2,7,1] ，得 -5 * -10 = 50 分，累加到分数中。\n- 选择开头处的整数 -3 ，[<strong>-3</strong>,-3,-2,7,1] ，得 -3 * -5 = 15 分，累加到分数中。\n- 选择开头处的整数 -3 ，[<strong>-3</strong>,-2,7,1] ，得 -3 * 3 = -9 分，累加到分数中。\n- 选择末尾处的整数 1 ，[-2,7,<strong>1</strong>] ，得 1 * 4 = 4 分，累加到分数中。\n- 选择末尾处的整数 7 ，[-2,<strong>7</strong>] ，得 7 * 6 = 42 分，累加到分数中。\n总分数为 50 + 15 - 9 + 4 + 42 = 102 。\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>n == nums.length</code></li>\n\t<li><code>m == multipliers.length</code></li>\n\t<li><code>1 &lt;= m &lt;= 10<sup>3</sup></code></li>\n\t<li><code>m &lt;= n &lt;= 10<sup>5</sup></code><code> </code></li>\n\t<li><code>-1000 &lt;= nums[i], multipliers[i] &lt;= 1000</code></li>\n</ul>\n",
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