leetcode-problemset/leetcode-cn/originData/maximum-profit-in-job-scheduling.json

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        "question": {
            "questionId": "1352",
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            "title": "Maximum Profit in Job Scheduling",
            "titleSlug": "maximum-profit-in-job-scheduling",
            "content": "<p>We have <code>n</code> jobs, where every job is scheduled to be done from <code>startTime[i]</code> to <code>endTime[i]</code>, obtaining a profit of <code>profit[i]</code>.</p>\n\n<p>You&#39;re given the <code>startTime</code>, <code>endTime</code> and <code>profit</code> arrays, return the maximum profit you can take such that there are no two jobs in the subset with overlapping time range.</p>\n\n<p>If you choose a job that ends at time <code>X</code> you will be able to start another job that starts at time <code>X</code>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<p><strong><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2019/10/10/sample1_1584.png\" style=\"width: 380px; height: 154px;\" /></strong></p>\n\n<pre>\n<strong>Input:</strong> startTime = [1,2,3,3], endTime = [3,4,5,6], profit = [50,10,40,70]\n<strong>Output:</strong> 120\n<strong>Explanation:</strong> The subset chosen is the first and fourth job. \nTime range [1-3]+[3-6] , we get profit of 120 = 50 + 70.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<p><strong><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2019/10/10/sample22_1584.png\" style=\"width: 600px; height: 112px;\" /> </strong></p>\n\n<pre>\n<strong>Input:</strong> startTime = [1,2,3,4,6], endTime = [3,5,10,6,9], profit = [20,20,100,70,60]\n<strong>Output:</strong> 150\n<strong>Explanation:</strong> The subset chosen is the first, fourth and fifth job. \nProfit obtained 150 = 20 + 70 + 60.\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<p><strong><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2019/10/10/sample3_1584.png\" style=\"width: 400px; height: 112px;\" /></strong></p>\n\n<pre>\n<strong>Input:</strong> startTime = [1,1,1], endTime = [2,3,4], profit = [5,6,4]\n<strong>Output:</strong> 6\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= startTime.length == endTime.length == profit.length &lt;= 5 * 10<sup>4</sup></code></li>\n\t<li><code>1 &lt;= startTime[i] &lt; endTime[i] &lt;= 10<sup>9</sup></code></li>\n\t<li><code>1 &lt;= profit[i] &lt;= 10<sup>4</sup></code></li>\n</ul>\n",
            "translatedTitle": "规划兼职工作",
            "translatedContent": "<p>你打算利用空闲时间来做兼职工作赚些零花钱。</p>\n\n<p>这里有&nbsp;<code>n</code>&nbsp;份兼职工作，每份工作预计从&nbsp;<code>startTime[i]</code>&nbsp;开始到&nbsp;<code>endTime[i]</code>&nbsp;结束，报酬为&nbsp;<code>profit[i]</code>。</p>\n\n<p>给你一份兼职工作表，包含开始时间&nbsp;<code>startTime</code>，结束时间&nbsp;<code>endTime</code>&nbsp;和预计报酬&nbsp;<code>profit</code>&nbsp;三个数组，请你计算并返回可以获得的最大报酬。</p>\n\n<p>注意，时间上出现重叠的 2 份工作不能同时进行。</p>\n\n<p>如果你选择的工作在时间&nbsp;<code>X</code>&nbsp;结束，那么你可以立刻进行在时间&nbsp;<code>X</code>&nbsp;开始的下一份工作。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<p><strong><img alt=\"\" src=\"https://assets.leetcode-cn.com/aliyun-lc-upload/uploads/2019/10/19/sample1_1584.png\" style=\"width: 300px;\"></strong></p>\n\n<pre><strong>输入：</strong>startTime = [1,2,3,3], endTime = [3,4,5,6], profit = [50,10,40,70]\n<strong>输出：</strong>120\n<strong>解释：\n</strong>我们选出第 1 份和第 4 份工作， \n时间范围是 [1-3]+[3-6]，共获得报酬 120 = 50 + 70。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<p><strong><img alt=\"\" src=\"https://assets.leetcode-cn.com/aliyun-lc-upload/uploads/2019/10/19/sample22_1584.png\" style=\"height: 112px; width: 600px;\"> </strong></p>\n\n<pre><strong>输入：</strong>startTime = [1,2,3,4,6], endTime = [3,5,10,6,9], profit = [20,20,100,70,60]\n<strong>输出：</strong>150\n<strong>解释：\n</strong>我们选择第 1，4，5 份工作。 \n共获得报酬 150 = 20 + 70 + 60。\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<p><strong><img alt=\"\" src=\"https://assets.leetcode-cn.com/aliyun-lc-upload/uploads/2019/10/19/sample3_1584.png\" style=\"height: 112px; width: 400px;\"></strong></p>\n\n<pre><strong>输入：</strong>startTime = [1,1,1], endTime = [2,3,4], profit = [5,6,4]\n<strong>输出：</strong>6\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= startTime.length == endTime.length ==&nbsp;profit.length&nbsp;&lt;= 5 * 10^4</code></li>\n\t<li><code>1 &lt;=&nbsp;startTime[i] &lt;&nbsp;endTime[i] &lt;= 10^9</code></li>\n\t<li><code>1 &lt;=&nbsp;profit[i] &lt;= 10^4</code></li>\n</ul>\n",
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