leetcode-problemset/leetcode-cn/originData/maximum-of-absolute-value-expression.json

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        "question": {
            "questionId": "1230",
            "questionFrontendId": "1131",
            "categoryTitle": "Algorithms",
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            "title": "Maximum of Absolute Value Expression",
            "titleSlug": "maximum-of-absolute-value-expression",
            "content": "<p>Given two arrays of integers with equal lengths, return the maximum value of:</p>\r\n\r\n<p><code>|arr1[i] - arr1[j]| + |arr2[i] - arr2[j]| + |i - j|</code></p>\r\n\r\n<p>where the maximum is taken over all <code>0 &lt;= i, j &lt; arr1.length</code>.</p>\r\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> arr1 = [1,2,3,4], arr2 = [-1,4,5,6]\n<strong>Output:</strong> 13\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> arr1 = [1,-2,-5,0,10], arr2 = [0,-2,-1,-7,-4]\n<strong>Output:</strong> 20\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>2 &lt;= arr1.length == arr2.length &lt;= 40000</code></li>\n\t<li><code>-10^6 &lt;= arr1[i], arr2[i] &lt;= 10^6</code></li>\n</ul>\n",
            "translatedTitle": "绝对值表达式的最大值",
            "translatedContent": "<p>给你两个长度相等的整数数组，返回下面表达式的最大值：</p>\n\n<p><code>|arr1[i] - arr1[j]| + |arr2[i] - arr2[j]| + |i - j|</code></p>\n\n<p>其中下标 <code>i</code>，<code>j</code> 满足&nbsp;<code>0 &lt;= i, j &lt; arr1.length</code>。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre><strong>输入：</strong>arr1 = [1,2,3,4], arr2 = [-1,4,5,6]\n<strong>输出：</strong>13\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre><strong>输入：</strong>arr1 = [1,-2,-5,0,10], arr2 = [0,-2,-1,-7,-4]\n<strong>输出：</strong>20</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>2 &lt;= arr1.length == arr2.length &lt;= 40000</code></li>\n\t<li><code>-10^6 &lt;= arr1[i], arr2[i] &lt;= 10^6</code></li>\n</ul>\n",
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                "Use the idea that abs(A) + abs(B) = max(A+B, A-B, -A+B, -A-B)."
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