mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
synced 2025-01-10 18:48:13 +08:00
171 lines
21 KiB
JSON
171 lines
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"title": "Maximum Ascending Subarray Sum",
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"content": "<p>Given an array of positive integers <code>nums</code>, return the <em>maximum possible sum of an <strong>ascending</strong> subarray in </em><code>nums</code>.</p>\n\n<p>A subarray is defined as a contiguous sequence of numbers in an array.</p>\n\n<p>A subarray <code>[nums<sub>l</sub>, nums<sub>l+1</sub>, ..., nums<sub>r-1</sub>, nums<sub>r</sub>]</code> is <strong>ascending</strong> if for all <code>i</code> where <code>l <= i < r</code>, <code>nums<sub>i </sub> < nums<sub>i+1</sub></code>. Note that a subarray of size <code>1</code> is <strong>ascending</strong>.</p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [10,20,30,5,10,50]\n<strong>Output:</strong> 65\n<strong>Explanation: </strong>[5,10,50] is the ascending subarray with the maximum sum of 65.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [10,20,30,40,50]\n<strong>Output:</strong> 150\n<strong>Explanation: </strong>[10,20,30,40,50] is the ascending subarray with the maximum sum of 150.\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [12,17,15,13,10,11,12]\n<strong>Output:</strong> 33\n<strong>Explanation: </strong>[10,11,12] is the ascending subarray with the maximum sum of 33.\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 <= nums.length <= 100</code></li>\n\t<li><code>1 <= nums[i] <= 100</code></li>\n</ul>\n",
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"translatedTitle": "最大升序子数组和",
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"translatedContent": "<p>给你一个正整数组成的数组 <code>nums</code> ，返回 <code>nums</code> 中一个 <strong>升序 </strong>子数组的最大可能元素和。</p>\n\n<p>子数组是数组中的一个连续数字序列。</p>\n\n<p>已知子数组 <code>[nums<sub>l</sub>, nums<sub>l+1</sub>, ..., nums<sub>r-1</sub>, nums<sub>r</sub>]</code> ，若对所有 <code>i</code>（<code>l <= i < r</code>），<code>nums<sub>i </sub> < nums<sub>i+1</sub></code> 都成立，则称这一子数组为 <strong>升序</strong> 子数组。注意，大小为 <code>1</code> 的子数组也视作 <strong>升序</strong> 子数组。</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [10,20,30,5,10,50]\n<strong>输出：</strong>65\n<strong>解释：</strong>[5,10,50] 是元素和最大的升序子数组，最大元素和为 65 。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [10,20,30,40,50]\n<strong>输出：</strong>150\n<strong>解释：</strong>[10,20,30,40,50] 是元素和最大的升序子数组，最大元素和为 150 。 \n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [12,17,15,13,10,11,12]\n<strong>输出：</strong>33\n<strong>解释：</strong>[10,11,12] 是元素和最大的升序子数组，最大元素和为 33 。 \n</pre>\n\n<p><strong>示例 4：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [100,10,1]\n<strong>输出：</strong>100\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 <= nums.length <= 100</code></li>\n\t<li><code>1 <= nums[i] <= 100</code></li>\n</ul>\n",
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