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"categoryTitle": "Algorithms",
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"title": "Jump Game VI",
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"content": "<p>You are given a <strong>0-indexed</strong> integer array <code>nums</code> and an integer <code>k</code>.</p>\n\n<p>You are initially standing at index <code>0</code>. In one move, you can jump at most <code>k</code> steps forward without going outside the boundaries of the array. That is, you can jump from index <code>i</code> to any index in the range <code>[i + 1, min(n - 1, i + k)]</code> <strong>inclusive</strong>.</p>\n\n<p>You want to reach the last index of the array (index <code>n - 1</code>). Your <strong>score</strong> is the <strong>sum</strong> of all <code>nums[j]</code> for each index <code>j</code> you visited in the array.</p>\n\n<p>Return <em>the <strong>maximum score</strong> you can get</em>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [<u>1</u>,<u>-1</u>,-2,<u>4</u>,-7,<u>3</u>], k = 2\n<strong>Output:</strong> 7\n<strong>Explanation:</strong> You can choose your jumps forming the subsequence [1,-1,4,3] (underlined above). The sum is 7.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [<u>10</u>,-5,-2,<u>4</u>,0,<u>3</u>], k = 3\n<strong>Output:</strong> 17\n<strong>Explanation:</strong> You can choose your jumps forming the subsequence [10,4,3] (underlined above). The sum is 17.\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,-5,-20,4,-1,3,-6,-3], k = 2\n<strong>Output:</strong> 0\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length, k &lt;= 10<sup>5</sup></code></li>\n\t<li><code>-10<sup>4</sup> &lt;= nums[i] &lt;= 10<sup>4</sup></code></li>\n</ul>\n",
"translatedTitle": "跳跃游戏 VI",
"translatedContent": "<p>给你一个下标从 <strong>0</strong> 开始的整数数组 <code>nums</code> 和一个整数 <code>k</code> 。</p>\n\n<p>一开始你在下标 <code>0</code> 处。每一步,你最多可以往前跳 <code>k</code> 步,但你不能跳出数组的边界。也就是说,你可以从下标 <code>i</code> 跳到 <code>[i + 1 min(n - 1, i + k)]</code> <strong>包含</strong> 两个端点的任意位置。</p>\n\n<p>你的目标是到达数组最后一个位置(下标为 <code>n - 1</code> ),你的 <strong>得分</strong> 为经过的所有数字之和。</p>\n\n<p>请你返回你能得到的 <strong>最大得分</strong> 。</p>\n\n<p> </p>\n\n<p><strong>示例 1</strong></p>\n\n<pre>\n<b>输入:</b>nums = [<strong>1</strong>,<strong>-1</strong>,-2,<strong>4</strong>,-7,<strong>3</strong>], k = 2\n<b>输出:</b>7\n<b>解释:</b>你可以选择子序列 [1,-1,4,3] (上面加粗的数字),和为 7 。\n</pre>\n\n<p><strong>示例 2</strong></p>\n\n<pre>\n<strong>输入:</strong>nums = [<strong>10</strong>,-5,-2,<strong>4</strong>,0,<strong>3</strong>], k = 3\n<b>输出:</b>17\n<b>解释:</b>你可以选择子序列 [10,4,3] (上面加粗数字),和为 17 。\n</pre>\n\n<p><strong>示例 3</strong></p>\n\n<pre>\n<b>输入:</b>nums = [1,-5,-20,4,-1,3,-6,-3], k = 2\n<b>输出:</b>0\n</pre>\n\n<p> </p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li> <code>1 <= nums.length, k <= 10<sup>5</sup></code></li>\n\t<li><code>-10<sup>4</sup> <= nums[i] <= 10<sup>4</sup></code></li>\n</ul>\n",
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"Let dp[i] be \"the maximum score to reach the end starting at index i\". The answer for dp[i] is nums[i] + max{dp[i+j]} for 1 <= j <= k. That gives an O(n*k) solution.",
"Instead of checking every j for every i, keep track of the largest dp[i] values in a heap and calculate dp[i] from right to left. When the largest value in the heap is out of bounds of the current index, remove it and keep checking."
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