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{
"data": {
"question": {
"questionId": "933",
"questionFrontendId": "897",
"categoryTitle": "Algorithms",
"boundTopicId": 1113,
"title": "Increasing Order Search Tree",
"titleSlug": "increasing-order-search-tree",
"content": "<p>Given the <code>root</code> of a binary search tree, rearrange the tree in <strong>in-order</strong> so that the leftmost node in the tree is now the root of the tree, and every node has no left child and only one right child.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/11/17/ex1.jpg\" style=\"width: 600px; height: 350px;\" />\n<pre>\n<strong>Input:</strong> root = [5,3,6,2,4,null,8,1,null,null,null,7,9]\n<strong>Output:</strong> [1,null,2,null,3,null,4,null,5,null,6,null,7,null,8,null,9]\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/11/17/ex2.jpg\" style=\"width: 300px; height: 114px;\" />\n<pre>\n<strong>Input:</strong> root = [5,1,7]\n<strong>Output:</strong> [1,null,5,null,7]\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li>The number of nodes in the given tree will be in the range <code>[1, 100]</code>.</li>\n\t<li><code>0 &lt;= Node.val &lt;= 1000</code></li>\n</ul>\n",
"translatedTitle": "递增顺序搜索树",
"translatedContent": "<p>给你一棵二叉搜索树的<meta charset=\"UTF-8\" />&nbsp;<code>root</code>&nbsp;,请你 <strong>按中序遍历</strong> 将其重新排列为一棵递增顺序搜索树,使树中最左边的节点成为树的根节点,并且每个节点没有左子节点,只有一个右子节点。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/11/17/ex1.jpg\" style=\"height: 350px; width: 600px;\" />\n<pre>\n<strong>输入:</strong>root = [5,3,6,2,4,null,8,1,null,null,null,7,9]\n<strong>输出:</strong>[1,null,2,null,3,null,4,null,5,null,6,null,7,null,8,null,9]\n</pre>\n\n<p><strong>示例 2</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/11/17/ex2.jpg\" style=\"height: 114px; width: 300px;\" />\n<pre>\n<strong>输入:</strong>root = [5,1,7]\n<strong>输出:</strong>[1,null,5,null,7]\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li>树中节点数的取值范围是 <code>[1, 100]</code></li>\n\t<li><code>0 &lt;= Node.val &lt;= 1000</code></li>\n</ul>\n",
"isPaidOnly": false,
"difficulty": "Easy",
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"topicTags": [
{
"name": "Stack",
"slug": "stack",
"translatedName": "栈",
"__typename": "TopicTagNode"
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{
"name": "Tree",
"slug": "tree",
"translatedName": "树",
"__typename": "TopicTagNode"
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{
"name": "Depth-First Search",
"slug": "depth-first-search",
"translatedName": "深度优先搜索",
"__typename": "TopicTagNode"
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{
"name": "Binary Search Tree",
"slug": "binary-search-tree",
"translatedName": "二叉搜索树",
"__typename": "TopicTagNode"
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{
"name": "Binary Tree",
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"code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n * public int val;\n * public TreeNode left;\n * public TreeNode right;\n * public TreeNode(int val=0, TreeNode left=null, TreeNode right=null) {\n * this.val = val;\n * this.left = left;\n * this.right = right;\n * }\n * }\n */\npublic class Solution {\n public TreeNode IncreasingBST(TreeNode root) {\n\n }\n}",
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"lang": "JavaScript",
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"code": "/**\n * Definition for a binary tree node.\n * function TreeNode(val, left, right) {\n * this.val = (val===undefined ? 0 : val)\n * this.left = (left===undefined ? null : left)\n * this.right = (right===undefined ? null : right)\n * }\n */\n/**\n * @param {TreeNode} root\n * @return {TreeNode}\n */\nvar increasingBST = function(root) {\n\n};",
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"code": "/**\n * Definition for a binary tree node.\n * class TreeNode {\n * val: number\n * left: TreeNode | null\n * right: TreeNode | null\n * constructor(val?: number, left?: TreeNode | null, right?: TreeNode | null) {\n * this.val = (val===undefined ? 0 : val)\n * this.left = (left===undefined ? null : left)\n * this.right = (right===undefined ? null : right)\n * }\n * }\n */\n\nfunction increasingBST(root: TreeNode | null): TreeNode | null {\n \n};",
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"lang": "Swift",
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"code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n * public var val: Int\n * public var left: TreeNode?\n * public var right: TreeNode?\n * public init() { self.val = 0; self.left = nil; self.right = nil; }\n * public init(_ val: Int) { self.val = val; self.left = nil; self.right = nil; }\n * public init(_ val: Int, _ left: TreeNode?, _ right: TreeNode?) {\n * self.val = val\n * self.left = left\n * self.right = right\n * }\n * }\n */\nclass Solution {\n func increasingBST(_ root: TreeNode?) -> TreeNode? {\n\n }\n}",
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"code": "/**\n * Example:\n * var ti = TreeNode(5)\n * var v = ti.`val`\n * Definition for a binary tree node.\n * class TreeNode(var `val`: Int) {\n * var left: TreeNode? = null\n * var right: TreeNode? = null\n * }\n */\nclass Solution {\n fun increasingBST(root: TreeNode?): TreeNode? {\n\n }\n}",
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"code": "/**\n * Definition for a binary tree node.\n * class TreeNode {\n * int val;\n * TreeNode? left;\n * TreeNode? right;\n * TreeNode([this.val = 0, this.left, this.right]);\n * }\n */\nclass Solution {\n TreeNode? increasingBST(TreeNode? root) {\n \n }\n}",
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"lang": "Go",
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"code": "/**\n * Definition for a binary tree node.\n * type TreeNode struct {\n * Val int\n * Left *TreeNode\n * Right *TreeNode\n * }\n */\nfunc increasingBST(root *TreeNode) *TreeNode {\n\n}",
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"code": "# Definition for a binary tree node.\n# class TreeNode\n# attr_accessor :val, :left, :right\n# def initialize(val = 0, left = nil, right = nil)\n# @val = val\n# @left = left\n# @right = right\n# end\n# end\n# @param {TreeNode} root\n# @return {TreeNode}\ndef increasing_bst(root)\n\nend",
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"code": "/**\n * Definition for a binary tree node.\n * class TreeNode(_value: Int = 0, _left: TreeNode = null, _right: TreeNode = null) {\n * var value: Int = _value\n * var left: TreeNode = _left\n * var right: TreeNode = _right\n * }\n */\nobject Solution {\n def increasingBST(root: TreeNode): TreeNode = {\n\n }\n}",
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"code": "// Definition for a binary tree node.\n// #[derive(Debug, PartialEq, Eq)]\n// pub struct TreeNode {\n// pub val: i32,\n// pub left: Option<Rc<RefCell<TreeNode>>>,\n// pub right: Option<Rc<RefCell<TreeNode>>>,\n// }\n//\n// impl TreeNode {\n// #[inline]\n// pub fn new(val: i32) -> Self {\n// TreeNode {\n// val,\n// left: None,\n// right: None\n// }\n// }\n// }\nuse std::rc::Rc;\nuse std::cell::RefCell;\nimpl Solution {\n pub fn increasing_bst(root: Option<Rc<RefCell<TreeNode>>>) -> Option<Rc<RefCell<TreeNode>>> {\n\n }\n}",
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{
"lang": "Racket",
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"code": "; Definition for a binary tree node.\n#|\n\n; val : integer?\n; left : (or/c tree-node? #f)\n; right : (or/c tree-node? #f)\n(struct tree-node\n (val left right) #:mutable #:transparent)\n\n; constructor\n(define (make-tree-node [val 0])\n (tree-node val #f #f))\n\n|#\n\n(define/contract (increasing-bst root)\n (-> (or/c tree-node? #f) (or/c tree-node? #f))\n )",
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"lang": "Elixir",
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"code": "# Definition for a binary tree node.\n#\n# defmodule TreeNode do\n# @type t :: %__MODULE__{\n# val: integer,\n# left: TreeNode.t() | nil,\n# right: TreeNode.t() | nil\n# }\n# defstruct val: 0, left: nil, right: nil\n# end\n\ndefmodule Solution do\n @spec increasing_bst(root :: TreeNode.t | nil) :: TreeNode.t | nil\n def increasing_bst(root) do\n \n end\nend",
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