leetcode-problemset/leetcode-cn/originData/gas-station.json

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            "title": "Gas Station",
            "titleSlug": "gas-station",
            "content": "<p>There are <code>n</code> gas stations along a circular route, where the amount of gas at the <code>i<sup>th</sup></code> station is <code>gas[i]</code>.</p>\n\n<p>You have a car with an unlimited gas tank and it costs <code>cost[i]</code> of gas to travel from the <code>i<sup>th</sup></code> station to its next <code>(i + 1)<sup>th</sup></code> station. You begin the journey with an empty tank at one of the gas stations.</p>\n\n<p>Given two integer arrays <code>gas</code> and <code>cost</code>, return <em>the starting gas station&#39;s index if you can travel around the circuit once in the clockwise direction, otherwise return</em> <code>-1</code>. If there exists a solution, it is <strong>guaranteed</strong> to be <strong>unique</strong></p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> gas = [1,2,3,4,5], cost = [3,4,5,1,2]\n<strong>Output:</strong> 3\n<strong>Explanation:</strong>\nStart at station 3 (index 3) and fill up with 4 unit of gas. Your tank = 0 + 4 = 4\nTravel to station 4. Your tank = 4 - 1 + 5 = 8\nTravel to station 0. Your tank = 8 - 2 + 1 = 7\nTravel to station 1. Your tank = 7 - 3 + 2 = 6\nTravel to station 2. Your tank = 6 - 4 + 3 = 5\nTravel to station 3. The cost is 5. Your gas is just enough to travel back to station 3.\nTherefore, return 3 as the starting index.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> gas = [2,3,4], cost = [3,4,3]\n<strong>Output:</strong> -1\n<strong>Explanation:</strong>\nYou can&#39;t start at station 0 or 1, as there is not enough gas to travel to the next station.\nLet&#39;s start at station 2 and fill up with 4 unit of gas. Your tank = 0 + 4 = 4\nTravel to station 0. Your tank = 4 - 3 + 2 = 3\nTravel to station 1. Your tank = 3 - 3 + 3 = 3\nYou cannot travel back to station 2, as it requires 4 unit of gas but you only have 3.\nTherefore, you can&#39;t travel around the circuit once no matter where you start.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>n == gas.length == cost.length</code></li>\n\t<li><code>1 &lt;= n &lt;= 10<sup>5</sup></code></li>\n\t<li><code>0 &lt;= gas[i], cost[i] &lt;= 10<sup>4</sup></code></li>\n</ul>\n",
            "translatedTitle": "加油站",
            "translatedContent": "<p>在一条环路上有 <code>n</code>&nbsp;个加油站，其中第 <code>i</code>&nbsp;个加油站有汽油&nbsp;<code>gas[i]</code><em>&nbsp;</em>升。</p>\n\n<p>你有一辆油箱容量无限的的汽车，从第<em> </em><code>i</code><em> </em>个加油站开往第<em> </em><code>i+1</code><em>&nbsp;</em>个加油站需要消耗汽油&nbsp;<code>cost[i]</code><em>&nbsp;</em>升。你从其中的一个加油站出发，开始时油箱为空。</p>\n\n<p>给定两个整数数组 <code>gas</code> 和 <code>cost</code> ，如果你可以按顺序绕环路行驶一周，则返回出发时加油站的编号，否则返回 <code>-1</code> 。如果存在解，则 <strong>保证</strong> 它是 <strong>唯一</strong> 的。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例&nbsp;1:</strong></p>\n\n<pre>\n<strong>输入:</strong> gas = [1,2,3,4,5], cost = [3,4,5,1,2]\n<strong>输出:</strong> 3\n<strong>解释:\n</strong>从 3 号加油站(索引为 3 处)出发，可获得 4 升汽油。此时油箱有 = 0 + 4 = 4 升汽油\n开往 4 号加油站，此时油箱有 4 - 1 + 5 = 8 升汽油\n开往 0 号加油站，此时油箱有 8 - 2 + 1 = 7 升汽油\n开往 1 号加油站，此时油箱有 7 - 3 + 2 = 6 升汽油\n开往 2 号加油站，此时油箱有 6 - 4 + 3 = 5 升汽油\n开往 3 号加油站，你需要消耗 5 升汽油，正好足够你返回到 3 号加油站。\n因此，3 可为起始索引。</pre>\n\n<p><strong>示例 2:</strong></p>\n\n<pre>\n<strong>输入:</strong> gas = [2,3,4], cost = [3,4,3]\n<strong>输出:</strong> -1\n<strong>解释:\n</strong>你不能从 0 号或 1 号加油站出发，因为没有足够的汽油可以让你行驶到下一个加油站。\n我们从 2 号加油站出发，可以获得 4 升汽油。 此时油箱有 = 0 + 4 = 4 升汽油\n开往 0 号加油站，此时油箱有 4 - 3 + 2 = 3 升汽油\n开往 1 号加油站，此时油箱有 3 - 3 + 3 = 3 升汽油\n你无法返回 2 号加油站，因为返程需要消耗 4 升汽油，但是你的油箱只有 3 升汽油。\n因此，无论怎样，你都不可能绕环路行驶一周。</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>gas.length == n</code></li>\n\t<li><code>cost.length == n</code></li>\n\t<li><code>1 &lt;= n &lt;= 10<sup>5</sup></code></li>\n\t<li><code>0 &lt;= gas[i], cost[i] &lt;= 10<sup>4</sup></code></li>\n</ul>\n",
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