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leetcode-problemset/leetcode-cn/originData/find-two-non-overlapping-sub-arrays-each-with-target-sum.json
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"categoryTitle": "Algorithms",
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"title": "Find Two Non-overlapping Sub-arrays Each With Target Sum",
"titleSlug": "find-two-non-overlapping-sub-arrays-each-with-target-sum",
"content": "<p>You are given an array of integers <code>arr</code> and an integer <code>target</code>.</p>\n\n<p>You have to find <strong>two non-overlapping sub-arrays</strong> of <code>arr</code> each with a sum equal <code>target</code>. There can be multiple answers so you have to find an answer where the sum of the lengths of the two sub-arrays is <strong>minimum</strong>.</p>\n\n<p>Return <em>the minimum sum of the lengths</em> of the two required sub-arrays, or return <code>-1</code> if you cannot find such two sub-arrays.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> arr = [3,2,2,4,3], target = 3\n<strong>Output:</strong> 2\n<strong>Explanation:</strong> Only two sub-arrays have sum = 3 ([3] and [3]). The sum of their lengths is 2.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> arr = [7,3,4,7], target = 7\n<strong>Output:</strong> 2\n<strong>Explanation:</strong> Although we have three non-overlapping sub-arrays of sum = 7 ([7], [3,4] and [7]), but we will choose the first and third sub-arrays as the sum of their lengths is 2.\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> arr = [4,3,2,6,2,3,4], target = 6\n<strong>Output:</strong> -1\n<strong>Explanation:</strong> We have only one sub-array of sum = 6.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= arr.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= arr[i] &lt;= 1000</code></li>\n\t<li><code>1 &lt;= target &lt;= 10<sup>8</sup></code></li>\n</ul>\n",
"translatedTitle": "找两个和为目标值且不重叠的子数组",
"translatedContent": "<p>给你一个整数数组&nbsp;<code>arr</code> 和一个整数值&nbsp;<code>target</code>&nbsp;。</p>\n\n<p>请你在 <code>arr</code>&nbsp;中找 <strong>两个互不重叠的子数组</strong>&nbsp;且它们的和都等于&nbsp;<code>target</code>&nbsp;。可能会有多种方案,请你返回满足要求的两个子数组长度和的 <strong>最小值</strong> 。</p>\n\n<p>请返回满足要求的最小长度和,如果无法找到这样的两个子数组,请返回 <strong>-1</strong>&nbsp;。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1</strong></p>\n\n<pre><strong>输入:</strong>arr = [3,2,2,4,3], target = 3\n<strong>输出:</strong>2\n<strong>解释:</strong>只有两个子数组和为 3 [3] 和 [3])。它们的长度和为 2 。\n</pre>\n\n<p><strong>示例 2</strong></p>\n\n<pre><strong>输入:</strong>arr = [7,3,4,7], target = 7\n<strong>输出:</strong>2\n<strong>解释:</strong>尽管我们有 3 个互不重叠的子数组和为 7 [7], [3,4] 和 [7]),但我们会选择第一个和第三个子数组,因为它们的长度和 2 是最小值。\n</pre>\n\n<p><strong>示例 3</strong></p>\n\n<pre><strong>输入:</strong>arr = [4,3,2,6,2,3,4], target = 6\n<strong>输出:</strong>-1\n<strong>解释:</strong>我们只有一个和为 6 的子数组。\n</pre>\n\n<p><strong>示例 4</strong></p>\n\n<pre><strong>输入:</strong>arr = [5,5,4,4,5], target = 3\n<strong>输出:</strong>-1\n<strong>解释:</strong>我们无法找到和为 3 的子数组。\n</pre>\n\n<p><strong>示例 5</strong></p>\n\n<pre><strong>输入:</strong>arr = [3,1,1,1,5,1,2,1], target = 3\n<strong>输出:</strong>3\n<strong>解释:</strong>注意子数组 [1,2] 和 [2,1] 不能成为一个方案因为它们重叠了。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= arr.length &lt;= 10^5</code></li>\n\t<li><code>1 &lt;= arr[i] &lt;= 1000</code></li>\n\t<li><code>1 &lt;= target &lt;= 10^8</code></li>\n</ul>\n",
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"Let's create two arrays prefix and suffix where prefix[i] is the minimum length of sub-array ends before i and has sum = k, suffix[i] is the minimum length of sub-array starting at or after i and has sum = k.",
"The answer we are searching for is min(prefix[i] + suffix[i]) for all values of i from 0 to n-1 where n == arr.length.",
"If you are still stuck with how to build prefix and suffix, you can store for each index i the length of the sub-array starts at i and has sum = k or infinity otherwise, and you can use it to build both prefix and suffix."
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