leetcode-problemset/leetcode-cn/originData/find-polygon-with-the-largest-perimeter.json

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            "title": "Find Polygon With the Largest Perimeter",
            "titleSlug": "find-polygon-with-the-largest-perimeter",
            "content": "<p>You are given an array of <strong>positive</strong> integers <code>nums</code> of length <code>n</code>.</p>\n\n<p>A <strong>polygon</strong> is a closed plane figure that has at least <code>3</code> sides. The <strong>longest side</strong> of a polygon is <strong>smaller</strong> than the sum of its other sides.</p>\n\n<p>Conversely, if you have <code>k</code> (<code>k &gt;= 3</code>) <strong>positive</strong> real numbers <code>a<sub>1</sub></code>, <code>a<sub>2</sub></code>, <code>a<sub>3</sub></code>, ..., <code>a<sub>k</sub></code> where <code>a<sub>1</sub> &lt;= a<sub>2</sub> &lt;= a<sub>3</sub> &lt;= ... &lt;= a<sub>k</sub></code> <strong>and</strong> <code>a<sub>1</sub> + a<sub>2</sub> + a<sub>3</sub> + ... + a<sub>k-1</sub> &gt; a<sub>k</sub></code>, then there <strong>always</strong> exists a polygon with <code>k</code> sides whose lengths are <code>a<sub>1</sub></code>, <code>a<sub>2</sub></code>, <code>a<sub>3</sub></code>, ..., <code>a<sub>k</sub></code>.</p>\n\n<p>The <strong>perimeter</strong> of a polygon is the sum of lengths of its sides.</p>\n\n<p>Return <em>the <strong>largest</strong> possible <strong>perimeter</strong> of a <strong>polygon</strong> whose sides can be formed from</em> <code>nums</code>, <em>or</em> <code>-1</code> <em>if it is not possible to create a polygon</em>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [5,5,5]\n<strong>Output:</strong> 15\n<strong>Explanation:</strong> The only possible polygon that can be made from nums has 3 sides: 5, 5, and 5. The perimeter is 5 + 5 + 5 = 15.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,12,1,2,5,50,3]\n<strong>Output:</strong> 12\n<strong>Explanation:</strong> The polygon with the largest perimeter which can be made from nums has 5 sides: 1, 1, 2, 3, and 5. The perimeter is 1 + 1 + 2 + 3 + 5 = 12.\nWe cannot have a polygon with either 12 or 50 as the longest side because it is not possible to include 2 or more smaller sides that have a greater sum than either of them.\nIt can be shown that the largest possible perimeter is 12.\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [5,5,50]\n<strong>Output:</strong> -1\n<strong>Explanation:</strong> There is no possible way to form a polygon from nums, as a polygon has at least 3 sides and 50 &gt; 5 + 5.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>3 &lt;= n &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= nums[i] &lt;= 10<sup>9</sup></code></li>\n</ul>\n",
            "translatedTitle": "找到最大周长的多边形",
            "translatedContent": "<p>给你一个长度为&nbsp;<code>n</code>&nbsp;的&nbsp;<strong>正</strong>&nbsp;整数数组&nbsp;<code>nums</code>&nbsp;。</p>\n\n<p><strong>多边形</strong>&nbsp;指的是一个至少有 <code>3</code>&nbsp;条边的封闭二维图形。多边形的 <strong>最长边</strong>&nbsp;一定 <strong>小于</strong>&nbsp;所有其他边长度之和。</p>\n\n<p>如果你有&nbsp;<code>k</code>&nbsp;（<code>k &gt;= 3</code>）个&nbsp;<strong>正</strong>&nbsp;数&nbsp;<code>a<sub>1</sub></code>，<code>a<sub>2</sub></code>，<code>a<sub>3</sub></code>, ...，<code>a<sub>k</sub></code> 满足&nbsp;<code>a<sub>1</sub> &lt;= a<sub>2</sub> &lt;= a<sub>3</sub> &lt;= ... &lt;= a<sub>k</sub></code> <strong>且</strong> <code>a<sub>1</sub> + a<sub>2</sub> + a<sub>3</sub> + ... + a<sub>k-1</sub> &gt; a<sub>k</sub></code><sub>&nbsp;</sub>，那么 <strong>一定</strong>&nbsp;存在一个&nbsp;<code>k</code>&nbsp;条边的多边形，每条边的长度分别为&nbsp;<code>a<sub>1</sub></code>&nbsp;，<code>a<sub>2</sub></code>&nbsp;，<code>a<sub>3</sub></code>&nbsp;，&nbsp;...，<code>a<sub>k</sub></code>&nbsp;。</p>\n\n<p>一个多边形的 <strong>周长</strong>&nbsp;指的是它所有边之和。</p>\n\n<p>请你返回从 <code>nums</code>&nbsp;中可以构造的 <strong>多边形&nbsp;</strong>的 <strong>最大周长</strong>&nbsp;。如果不能构造出任何多边形，请你返回 <code>-1</code>&nbsp;。</p>\n\n<p>&nbsp;</p>\n\n<p><strong class=\"example\">示例 1：</strong></p>\n\n<pre>\n<b>输入：</b>nums = [5,5,5]\n<b>输出：</b>15\n<b>解释：</b>nums 中唯一可以构造的多边形为三角形，每条边的长度分别为 5 ，5 和 5 ，周长为 5 + 5 + 5 = 15 。\n</pre>\n\n<p><strong class=\"example\">示例 2：</strong></p>\n\n<pre>\n<b>输入：</b>nums = [1,12,1,2,5,50,3]\n<b>输出：</b>12\n<b>解释：</b>最大周长多边形为五边形，每条边的长度分别为 1 ，1 ，2 ，3 和 5 ，周长为 1 + 1 + 2 + 3 + 5 = 12 。\n我们无法构造一个包含变长为 12 或者 50 的多边形，因为其他边之和没法大于两者中的任何一个。\n所以最大周长为 12 。\n</pre>\n\n<p><strong class=\"example\">示例 3：</strong></p>\n\n<pre>\n<b>输入：</b>nums = [5,5,50]\n<b>输出：</b>-1\n<b>解释：</b>无法构造任何多边形，因为多边形至少要有 3 条边且 50 &gt; 5 + 5 。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>3 &lt;= n &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= nums[i] &lt;= 10<sup>9</sup></code></li>\n</ul>\n",
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